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stira [4]
3 years ago
12

BKS at a piece of paper along as diagonal, as shown below, towing two tendes

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

its the second option because it is clearly shown and described on the screen

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I want to be challenged more, so could anyone give me some 4th grade math problems​
nexus9112 [7]

I'm in 7th grade u want those math problems???

6 0
3 years ago
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How to solve the equation
tatiyna

Answer:

ha

Step-by-step explanation:

hahaha thanks for the points ha

8 0
2 years ago
find the volume of the following figure round your answer to the nearest tenth if necessary and make sure to use pi
Vikki [24]

Answer:

524cm^2

Step-by-step explanation:

Formula for Volume of sphere= 4/3 πr^2

We have,

r=5cm

Now,

Volume(v)=4/3 πr^2 = 4/3π 5^3= 4/3π 125 = 166.666666667π = 523.598775599

Rounding to the nearest tenth,

Volume=524cm^2

4 0
3 years ago
PLEASE HELP I've been struggling on this one :(
In-s [12.5K]

Answer: The answer is (x+2)(x-4)(x-4)
Or as a short form you can write it as
(x+2) (x-4)^{2}

Step-by-step explanation:

Answer is very lengthy but I am 100% sure that's the correct answer

6 0
2 years ago
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1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
scZoUnD [109]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<em>A) If the length of a rectangle was tripled, but the  width did not change?</em>

<em>Perimeter</em>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

<u>Area</u>

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em>

<u>Perimeter</u>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

<u><em>Area</em></u>

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

4 0
3 years ago
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