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2 years ago

I need help for all those please can someone please help me

Mathematics

1 answer:

aniked [119]2 years ago

4 0

Answer:

1. positive

2. negative

3. negative

4. positive

5. -2, 2

6. 3, -3

7. -5, 5

8. 1, -1

9. -4°F

10. 2°F

11. -8 ft

12. -282 ft

13. yes. the numbers are greater than 0 and less than 1. Such as 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9. They are integers.

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Just need help on the ones that are circled .

padilas [110]

2.) QR 3.) SW 6.) TW 8.) 7 9.) 30 11.) please supply a better picture for 11, can't see the problem very well

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2 years ago

Q #15 Graph ARTS With vertices R(6, 6), S(3, -6),and T(0, 3) and its image. over the Y -axis

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The rule of reflection over y-axis
(x,y) ⇒⇒⇒ (-x,y)
Note point T will not change
the solution is as shown in attached figure

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3 years ago

What is the next fraction in this sequence? Simplify 3/14,2/7,5/14,3/7, its due today please help

Fynjy0 [20]

The next fraction in the given sequence is; 7/14

We are given the sequence;

3/14, 2/7, 5/14, 3/7.

To get the next fraction in the sequence, we have to find the pattern of the differences.

Difference between first and second term is;

2/7 - 3/14 = 1/14

Similarly, for 2nd and 3rd term;

Difference = 5/14 - 2/7

Difference = 1/14

Therefore,the next fraction in the sequence will be gotten by adding 1/14 to 3/7

Next fraction = 3/7 + 1/14

Next fraction = 7/14

Read more on arithmetic sequence at;

brainly.com/question/1145052

7 0

2 years ago

How many triangles and quadrilaterals altogether can be formed using the vertices of a 7-sided regular polygon?

MAVERICK [17]

Answer: The correct option is

(E) 70.

Step-by-step explanation: We are given to find the number of triangles and quadrilaterals altogether that can be formed using the vertices of a 7-sided regular polygon.

To form a triangle, we need any 3 vertices of the 7-sided regular polygon. So, the number of triangles that can be formed is

$n_t=^7C_3=\dfrac{7!}{3!(7-3)!}=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}=35.$

Also, to form a quadrilateral, we need any 4 vertices of the 7-sided regular polygon. So, the number of quadrilateral that can be formed is

$n_q=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.$

Therefore, the total number of triangles and quadrilaterals is

$n=n_t+n_q=35+35=70.$

Thus, option (E) is CORRECT.

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2 years ago

Kianna has $2.83. Avery has $5.18. They put their money together to buy packages of fruit snacks that each cost $0.30. How many

Nana76 [90]

Answer:

26 snack packs

Step-by-step explanation:

2.83+5.18=8.01

8.01/.30=26.7

26 snack packs

7 0

2 years ago

Read 2 more answers