Answer:
part C. 3x + 2y <u>< </u>30, 5x + 7y <u><</u> 105
Step-by-step explanation:
Part 1:
spends 3 hours making each type X (3x)-each type x will take 3 hours so as the number of type x increases, the hours will increase by 3.
spends 2 hours making each type Y (2y)-each type y will take 2 hours so as the number of type y increases, the hours will increase by 2.
Part 2:
he can spend up to 30 hours each week making carvings. (<u><</u>30)-because he cannot spend more than 30 hours
Therefore, He has to spend 30 hours or less to make type X and type Y.
3x + 2y <u>< </u>30
Part 3:
His materials cost him $5 for each type X carving. (5x)-each type x will take $5 so as the number of type x increases, the cost will increase by 5.
His materials cost him $7 for each type Y carving, (7y)-each type y will take $7 so as the number of type y increases, the cost will increase by 7.
Part 4:
he must keep his weekly cost for materials to $105 or less (<u><</u>105)-total cost cannot be more than $105.
Therefore, the total cost of making x and y should be $105 or less.
5x + 7y <u><</u> 105
!!
Answer:
Step-by-step explanation:
We need to write this equation in y=mx+b where m is the slope.
3y= -2x +9
y= -2/3 +9
So now that it is in the form of y=mx+b, we can find the slope. -2/3 is the slope of the equation. Hope that helps!
5x - 3y = 11 ⇒ 5x - 3y = 11 ⇒ 5x - 3y = 11
x - 2y = 2 ⇒ -5(x - 3y) = 2 ⇒ <u>-5x + 15y = 2</u>
<u>12y</u> = <u>13</u>
12 12
y = 1 1/12
5x - 3(1 1/12) = 11
5x - 3 1/4 = 11
<u> +3 1/4 +3 1/4</u>
<u> 5x</u> = <u>14 1/4</u>
5 5
x = 2 17/20
(x, y) = (2 17/20, 1 1/12)
Answer:
single digit, for example= 6
interger power of 10 =10^8
Step-by-step explanation:
it will be written as
6*10^8
spoken as: six time 10 rais to the power of 8
Hello from MrBillDoesMath!
Answer:
Choice D, x-2
Discussion:
Observe the the highest order term in the numerator is x^4 and the highest order term in the denominator is x^3. So the highest order term in their quotient is x^4/x^3 = x. Choice D is the only possible answer as all other choices start with x^2
Regards,
MrB