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Dafna1 [17]
3 years ago
15

Find ST, where the endpoints S(-5,-1) and T(-2,3). Leave answer exact

Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

ST = 5

Step-by-step explanation:

Calculate ST using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with )x₁, y₁ ) = S(- 5, - 1) and (x₂, y₂ ) = T(- 2, 3)

ST = \sqrt{(-2+5)^2+(3+1)^2}

     = \sqrt{3^2+4^2}

    = \sqrt{9+16}

     = \sqrt{25}

      = 5

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How do you solve 3x+7=x
vredina [299]
3x + 7 = x

First, subtract 3x from both sides. / Your problem should look like: 7 = x - 3x
Second, simplify x - 3x to -2x. / Your problem should look like: 7 = -2x
Third, divide both sides by -2. / Your problem should look like: \frac{7}{-2} = x
Fourth, simplify \frac{7}{-2} to -\frac{7}{2} / Your problem should look like: - \frac{7}{2} = x
Fifth, switch sides. / Your problem should look like: x = -\frac{7}{2}

Answer as fraction: -\frac{7}{2}
Answer as decimal: -3.5


8 0
3 years ago
Read 2 more answers
One three and six are traingular list all the other triangular numbers up to 36
ArbitrLikvidat [17]
That isn’t a question it is a statement
3 0
3 years ago
Given a sample size n, how will the distribution of the sample mean behave?
Keith_Richards [23]
Answer:
Provided that the sample size, n, is sufficiently large (greater than 30), the distribution of sample means selected from a population will have a normal distribution, according to the Central Limit Theorem.

Explanation:
1. As n increases, the sample mean approaches the population mean
   (The Law of Large numbers)
2. The standard error of the sample is
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5 0
3 years ago
A- y= -3/2x+8<br> B- y=3/2x+5<br> C- y=2/3x+8<br> D- y=-2/3x+5
Annette [7]

Answer:

I think the right answer is B.

4 0
3 years ago
Sandy borrowed 6709 R.O from a bank to buy a piece of land. If the bank charges 12 1/3 % compounded each two months, what amount
enot [183]

Answer:

she is paying back 9112.5 R.O

Interest paid back is 2,403.95

Step-by-step explanation:

To find the amount, we use the compound interest formula.

This is given as;

A = I( 1 + r/n)^nt

where A is the amount we are trying to calculate

I is money borrowed = 6709

r is the interest rate = 12 1/3% = 37/3 = 12.33% which is same as 12.33/100 = 0.1233

n is the number of times interest is compounded. We have 15 2 months in 2 and a half years

t is the number of years = 2.5

Plugging these values, we have;

A = 6709(1 + 0.1233/15)^(15)(2.5)

A = 6709(1.0082)^(37.5)

A = 9112.95 R.O

Interest is amount - principal( money borrowed)

9112.95 - 6709 = 2403.95

4 0
3 years ago
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