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Dafna1 [17]
3 years ago
15

Find ST, where the endpoints S(-5,-1) and T(-2,3). Leave answer exact

Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

ST = 5

Step-by-step explanation:

Calculate ST using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with )x₁, y₁ ) = S(- 5, - 1) and (x₂, y₂ ) = T(- 2, 3)

ST = \sqrt{(-2+5)^2+(3+1)^2}

     = \sqrt{3^2+4^2}

    = \sqrt{9+16}

     = \sqrt{25}

      = 5

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gizmo_the_mogwai [7]

Answer:

a) -10

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Step-by-step explanation:

a) 2(x + 3) = x - 4

=  > 2x + 6 = x - 4

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=  > x =  - 10

b) 4(5x - 2) = 2(9x + 3)

=  > 20x -8 = 18x + 6

=  > 20x - 18x = 8 + 6

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Step-by-step explanation:

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3 years ago
A company is manufacturing an open-top rectangular box. They have 30 cm by 16 cm sheets of material. The bins are made by cuttin
Natalija [7]

Answer:

a. (30 - 2x)(16 - 2x)x. b. length 21.2 cm , width = 7.2 cm and height x = 4.4 cm

Step-by-step explanation:

a. Let x be the side of the squares to be cut from each corner. Since we have two corners on each side, the length of the resulting box from the 30 cm by 16 cm sheet is L = 30 - 2x. Its breadth is B = 16 - 2x. The height of the resulting box is x. So its volume V = LBx = (30 - 2x)(16 - 2x)x.

b. To find the maximum value of V, we differentiate V with respect to x and equate it to zero.

So, dV/dx = 0

d(30 - 2x)(16 - 2x)x/dx = 0

-2(16 - 2x)x + (-2)(30 - 2x)x + (30 - 2x)(16 - 2x) = 0

32x + 4x² - 60x - 4x² + 480 - 60x - 32x + 4x² = 0

4x²- 120x + 450 = 0

x²- 30x + 112.5 = 0

Using the quadratic formula, we find x. So, with a = 1, b = - 15 and c = 112.5,

x = \frac{-(-30)+/-\sqrt{(-30)^{2} - 4 X 1 X 112.5} }{2 X 1} \\= \frac{30+/-\sqrt{900 - 450} }{2}\\ = \frac{30+/-\sqrt{450} }{2}\\ = \frac{30+/-21.21 }{2}\\\\ = \frac{30+21.21 }{2}   or  \frac{30-21.21 }{2}\\ = \frac{51.21 }{2}   or  \frac{8.79}{2}\\ = 25.605 or 4.395

x ≅ 25.61 or 4.4

V = (30 - 2x)(16 - 2x)x

Substituting the values of x into L and B, we have )x

L = (30 - 2x) = (30 - 2(25.61)) = 30 - 51.22 = -21.22

B = (16 - 2x) = (16 - 2(25.61)) = 16 - 51.22 = -35.22

Since L and B cannot be negative, we use the other value for x = 4.4, So

L = (30 - 2x) = (30 - 2(4.4)) = 30 - 8.8 = 21.2

B = (16 - 2x) = (16 - 2(4.4)) = 16 - 8.8 = 7.2

So V = LBx = 21.2 × 7.2 × 4.4 = 671.62 cm³

3 0
3 years ago
The average (arithmetic mean) of y numbers is x. if 30 is added to the set of numbers, then the average will be x - 5. what is t
Anastasy [175]
Given,

AM of y numbers = x.

Let the sum of y numbers be s.

AM of y numbers = x

\frac{s}{y} = x

s = y*x

Given, when 30 is added to the y numbers, the AM becomes x - 5.

\frac{s + 30}{y + 1} = x - 5

\frac{y*x + 30}{y +1} = x - 5


y*x + 30 = (x -5)( y +1)

y*x + 30 = y*x + x - 5y -5

5y = x - 5 -30 = x - 35


y =  \frac{x -35}{5} 
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4 years ago
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Vladimir79 [104]

Answer:

-1

Step-by-step explanation:

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8 0
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