Answer:
The other midpoint is located at coordinates (-9,-2) (Second option)
Step-by-step explanation:
<u>Midpoints</u>
If P(a,b) and Q(c,d) are points in
, the midpoint between them is the point exactly in the center of the line that joins P and Q. Its coordinates are given by


We are given one endpoint at P(1,-2) and the midpoint at M(-4,-2). The other endpoint must be at an equal distance from the midpoint as it is from P. We can see both given points have the same value of y=-2. This simplifies the calculations because we only need to deal with the x-coordinate.
The x-distance from P to M is 1-(-4)=5 units. This means the other endpoint must be 5 units to the left of M:
x (other endpoint)= - 4 - 5 = - 9
So the other midpoint is located at (-9,-2) (Second option)
Answer:
go to the left 3.5 units then go down one and that's your point
Answer:
Step-by-step explanation:
HERE ARE THE ANSWERS
Answer:
76.2048 Kilograms
Step-by-step explanation:
You would multiply 168 by 0.4536
168 x 0.4536 = 76.2048
Here is dependence between scores and x-values:

where
is the mean,
is standard deviation and i changes from 1 to 2.
1. When i=1,
then

2. When i=2,
then

Now solve the system of equations:


Subtract first equation from the second:

Then

Answer: the mean is 62, the standard deviation is 20.