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ryzh [129]
3 years ago
3

Which pair of elements can form ionic bonds

Chemistry
2 answers:
il63 [147K]3 years ago
4 0

A pair of elements will most likely form an ionic bond if one is a metal and one is a nonmetal. These types of ionic compounds are composed of monatomic cations and anions.

Vaselesa [24]3 years ago
3 0

Answer: metal and non metsl

Explanation:

Generally ionic bonds are formed when Electronegativity difference between two bonded atoms is >1.7

And observed between metal and non metal

Example, NaCl, MgCl2 and Fecl3 etc

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buring of paper, burning of wood etc are the examples of chemical change

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The perimeter of a square ​
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The perimeter of a square is P=4a because a P stands for perimeter and it’s 4 because a square has 4 sides
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17. The correct arrangement of the following elements in order of
tatuchka [14]

Answer:

Got your back

Explanation:

If the ions derived from different atoms are isoelectronic species, then they all have same number of electrons in their electronic shells and will have got same electronic configuration but their nuclear charge will differ because of their difference in number of protons in the nucleus. With increase in number of protons in the nucleus the electrons are more attracted towards nucleus thereby causing the decrease in ionic radius. On this principle our problem will be solved

The given ions are

7N-3

→no. of proton

=7

and

no of electron

=10

8O-2

→

no. of proton

=8

and

no of electron

=10

9F-→

no. of proton=9

and no of electron=10

11Na→

no. of proton=11

and no of electron=10

12 Mg-3→

no. of proton=12 and

no of electron=10

Hence the increasing order of ionic radius is

12Mg-3<11Na+<9F-<8O-2<7N-3

To rmember ->For isoelectronic species lower the nuclear charge higher the radius

8 0
3 years ago
3.5g of a Certain compound X, known to be made of carbon, hydrogen, and perhaps oxygen, and to have a molecular molar mass of 15
shutvik [7]

Answer:

C₅H₁₀O₅

Explanation:

1. Calculate the mass of each element in 2.78 mg of X.

(a) Mass of C

\text{Mass of C} = \text{5.13 g CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{1.400 g C}

(b) Mass of H

\text{Mass of H} = \text{2.10 g H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g H$_{2}$O}} = \text{0.2349 g H}

(c) Mass of O

Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g

2. Calculate the moles of each element

\text{Moles of C = 1400  mg C}\times\dfrac{\text{1 mmol C}}{\text{12.01 mg C }} = \text{116.6 mmol C}\\\\\text{Moles of H = 234.9 mg H} \times \dfrac{\text{1 mmol H}}{\text{1.008 mg H}} = \text{233.1 mmol H}\\\\\text{Moles of O = 1870 mg O} \times \dfrac{\text{1 mmol O}}{\text{16.00 mg O}} = \text{116 mmol O}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{116.6}{116.6}= 1\\\\\text{H: } \dfrac{233.1}{116.6} = 1.999\\\\\text{O: } \dfrac{116}{116.6} = 1.00

4. Round the ratios to the nearest integer

C:H:O = 1:2:1

5. Write the empirical formula

The empirical formula is CH₂O.

6. Calculate the molecular formula.

EF Mass = (12.01 + 2.016  + 16.00) u  = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{150 u}}{\text{30.03 u}} = 5.00  \approx 5

MF = (CH₂O)₅ = C₅H₁₀O₅

The molecular formula of X is C₅H₁₀O₅.

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4 years ago
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Mashutka [201]
The correct answer is Conference committee.
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