Answer: did she conect the wire to de batery?
Answer:
0.052L
Explanation:
Molarity of a substance, which refers to the molar concentration, is calculated as follows:
Molarity (M) = number of moles (mol) ÷ volume (L)
Mole = mass ÷ molar mass
Molar Mass of AgNO3 since Ag = 108, N = 14, O = 16
108 + 14 + 16(3)
= 108 + 14 + 48
= 170g/mol
Mole = 21.89 g ÷ 170g/mol
Mole = 0.129moles
Using Molarity (M) = number of moles (mol) ÷ volume (L)
Volume = number of moles ÷ molarity
V = 0.129 ÷ 2.50
V = 0.0516
To the correct significant figure i.e. 4s.f, the numerical value of volume = 0.052L
Answer:
28.0mL of the 0.0500M NaOH solution
Explanation:
<em>0.126g of lactic acid diluted to 250mL. Titrated with 0.0500M NaOH solution.</em>
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The reaction of lactic acid, H₃C-CH(OH)-COOH (Molar mass: 90.08g/mol) with NaOH is:
H₃C-CH(OH)-COOH + NaOH → H₃C-CH(OH)-COO⁻ + Na⁺ + H₂O
<em>Where 1 mole of the acid reacts per mole of the base.</em>
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You must know the student will reach equivalence point when moles of lactic acid = moles NaOH.
the student will titrate the 0.126g of H₃C-CH(OH)-COOH. In moles (Using molar mass) are:
0.126g ₓ (1mol / 90.08g) = <em>1.40x10⁻³ moles of H₃C-CH(OH)-COOH</em>
To reach equivalence point, the student must add 1.40x10⁻³ moles of NaOH. These moles comes from:
1.40x10⁻³ moles of NaOH ₓ (1L / 0.0500moles NaOH) = 0.0280L of the 0.0500M NaOH =
<h3>28.0mL of the 0.0500M NaOH solution</h3>
Light and energy is captured by green pigment and chlorophyll molecules.
The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.
<u>Explanation:</u>
Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.
As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.
Hence, 
Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.
