When a carboxylic acid is treated with an alcohol and an acid catalyst, an ester is formed (along with water). This reaction is called the Fischer esterification.

4 0

2 years ago

Part A of the lab involved adding 4 mL increments of distilled water to 5.00 mL of antimony trichloride solution. The antimony t

Mrrafil [7]

Answer:

0.0238M SbCl3, 1.07M H+, 1.14M Cl-

Explanation:

The total volume of the solution is:

4mL + 5.00mL + 12.0mL = 21mL

As the volume of the SbCl3 is 5.00mL, the dilution factor is:

21mL / 5.00mL = 4.2 times

The concentration of SbCl3 is:

0.10M SbCl3 / 4.2 times = 0.0238M SbCl3

The concentration of H+ = [HCl]:

4.5M / 4.2 times = 1.07M H+

The initial concentration of Cl- is:

3 times SbCl3 + HCl = 0.10M*3 + 4.5M =

<em>3 times SbCl3 because 1 mole of SbCl3 contains 3 moles of Cl-</em>

4.8M Cl- / 4.2 times = 1.14M Cl-

3 0

2 years ago

QUICK HELP PLEASE!!?? Need answer QUICK

d1i1m1o1n [39]

Answer:

Explanation:

Look on the x-axis for the tick marked "60". This indicates 60 degrees Celsius, which we want. Now, look on the y-axis for the tick marked "60". This indicates 60 grams of $Na_2HAsO_4$ . Trace along the graph to find where these two places meet at (60, 60).

Now, look for the solubility curve of $Na_2HAsO_4$ ; it's the yellow-orange line. Find out what the y-coordinate of the point where x = 60 is on the line: it's around (60, 65).

So, since the point (60, 60) is below the line corresponding to this substance, $Na_2HAsO_4$ is unsaturated.

The answer is B.

4 0

3 years ago

Read 2 more answers

For the following reaction, 2 SO2(g) + O:(g) 2 SO,(g) the equilibrium constant, K, is 1.32 at 627°C. What is the equilibrium con

cupoosta [38]

Answer:

1.15

Explanation:

2SO₂ + O₂ ⟶ 2SO₃; K =1.32

SO₂ + ½O₂ ⟶ SO₃; K₁ = ?

When you divide an equation by 2, you take the square root of its equilibrium constant.

K₁ = √1.32 = 1.15

The equilibrium constant is 1.15.

8 0

3 years ago