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Tom [10]
3 years ago
12

Which of the following are likely to form an ionic bond

Chemistry
1 answer:
sattari [20]3 years ago
3 0

Answer:

No question is posted.

But Ionic bond is mostly between metals live Na, K, Ca, Mg and strong non metals like Cl, O, F

Explanation:

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Yes as there is advertisements for this as a alternative to glue.<span />
3 0
3 years ago
Determine the mass of NH4Cl that must be dissolved in 100. grams of H2O to produce a saturated solution at 70.°C.
Delvig [45]
If you look at your Chemistry reference table, the answer should be about 62g of NH4Cl. Lining up the lines of solubility and temperature, you should come to that answer.
3 0
3 years ago
What do the rows of the periodic table indicate?
Tanya [424]

Answer:

The rows on the periodic table are called periods. All the elements in a period have valence electrons in the same shell. The number of valence electrons increases from left to right in the period. When the shell is full, a new row is started and the process repeats.

Explanation:

hope this helps..

3 0
3 years ago
A hydrocarbon is burnt completely to give 3.447g of
goblinko [34]

<u>Answer:</u> The empirical formula for the given compound is CH_2

<u>Explanation:</u>

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y'  are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=3.447g

Mass of H_2O=1.647g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 3.447 g of carbon dioxide, \frac{12}{44}\times 3.447=0.940g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 1.647 g of water, \frac{2}{18}\times 1.647=0.183g of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.940g}{12g/mole}=0.0783moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.183g}{1g/mole}=0.183moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0783 moles.

For Carbon = \frac{0.0783}{0.0783}=1

For Hydrogen = \frac{0.183}{0.0783}=2.34\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 2

Hence, the empirical formula for the given compound is CH_2

8 0
4 years ago
Draw all resonance structures for the nitryl fluoride molecule, no2f.
denis-greek [22]
From  electronic  configuration valence electron of  Nitrogen is 5,  oxygen  6x2  which 12 since it  involve  two  molecules ,  that of is frulorine is  7, and  that No2F is 24  which  is  gotten  form  adding (5,12,7  ).All  resonance structure  are  as  follows
       F
 ..    I    ..
: O : N :O: 
 
              ..
     OR  : F:
              I                             

             N                                                  ..                                                                                                                                    : F:

          /         \                        or                   I

   ..                 ..                                               N

:O  :            :O:                                       / /        \\
                                                            / /               \\
                                                         :O :            :  O:
7 0
4 years ago
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