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emmainna [20.7K]
4 years ago
9

Please help me in here. And thx for da ' help

Mathematics
1 answer:
Ivanshal [37]4 years ago
6 0
No there isn’t enough water, 975 divided by 70 is 13.92 indicating there would only be enough water for 13 experiments and not 15
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PLZ ANSWER BEING TIMED!!!!!!!!!! WILL MARK BRAINLIEST GIVE THANKS AND MARK 5 STARS!!!!!!!
abruzzese [7]

Click on B, C, and E. The one that's symmetric is 300, the skewed one is room 240 and the greater of the 2 medians it 85 (the median of room 300)

5 0
3 years ago
HELPPP....PLEASE...........
kogti [31]

Answer:

9 1/3, 12 1/2, 14 3/4

Step-by-step explanation:

I assume the formula you’re working with is A=b*h since nothing says otherwise...

((Patio 1))

So you have your area (147) and your base (15 3/4), now you need to plug them in, which should look like this:

147= 15 3/4*h

You need to isolate your h in order to get the missing number, so you should divide both sides by 15 3/4 OR 63/4 ((15*3—>60+3=63))

Dividing by a fraction is the equivalent of multiplying by its reciprocal... so

147 * 4/63 = 588/63 which can be simplified to 84/9 once both the numerator and denominator are divided by 7

In mixed number for it is 9 3/9 which simplified becomes 9 1/3

You solve the other similarly

3 0
4 years ago
Suppose that Sin(θ)=5/13 and cos(θ)=-12/13. Find the value of tan(θ), cot (θ), CSC (θ), and sec (θ). Find the value of tan(2θ)
horrorfan [7]

Answer:

Because θ lies in quadrant II, 2θ must lie in quadrant IV. This means the tangent of 2θ is negative.

The adjacent side to θ is 7 because √(25²-24²)=7, so tanθ=7/24.

The double angle formula for tangent is tan 2θ = (2 tan θ) / (1 − tan² θ).

Substituting the value for tanθ in and keeping in mind that this is in quadrant IV, we get tan 2θ = -(2(7/24)/(1-(7/24)²)).  

Simplified, this becomes tan 2θ = -336/527.  

Therefore, the answer is C. -336/527.

5 0
3 years ago
The constraints of a problem are listed below. What are the vertices of the feasible region?
Grace [21]
The vertices are the intersections between the lines.

1) line x + y = 5 and y = 3:

y = 3 => x + 3 = 5 => x = 5 - 3 => x = 2

=> vertix = (2,3)

2) line x + y = 5 and y = 0

=> y = 0 => x + 0 = 5 => x = 5

=> vertix = (5,0)

3) line x + y = 5 and x = 0

=> 0 + y = 5 => y = 5

=>  (0,5) ------> this is not a vertix because it is above the line y = 3

4) line y = 3 and x-axis

=> vertix = (0,3)

5) x-axis and y-axis => origin => vertix = (0,0)

So, there are four vertices: (0,0), (5,0), (2,3) and (0,3)

Answer: That is the first option:(<span>0, 0), (0, 3), (2, 3), (5, 0)</span>
8 0
3 years ago
Read 2 more answers
11 32 37 4 47 39 calculate number not to come out
romanna [79]

Answer:

54

Step-by-step explanation:

I don't know how I did it but I feel it in my bones.

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