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inna [77]
3 years ago
7

Before a party, Audrey goes to the store with $55. She spends $52.92 on 12 cases of soda.

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0

Answer:

A case of soda costs $4.41.

No, she does not have enough for another case because 52.92 + 4.41 is 57.35 and that is over than what she has.

Step-by-step explanation:

52.92 / 12 = 4.41.

Hope this helps & best of luck!

Feel free to message me if you need more help! :)

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B "it's" means (it is) and that would not make sense if it fell on it is side .
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The ratio of square H’s length to square I’s length is 3 : 5. If the length of square H is 18 meters, what is the perimeter of s
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Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x &gt; 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
Calculate the following:
stiv31 [10]

Answer:

1.6238 × 10^8

Step-by-step explanation:

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