Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer: Choice A, -1540 feet
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Explanation:
Multiply the rate (44 ft per sec) by the number of seconds (35) to get 44*35 = 1540
The answer will be negative to indicate that the altitude has gone down. If you put in a positive change, then the altitude would go up. So that's why the answer is choice A
Note: when you multiply 44 ft/sec by 35 sec, the "second" units cancel out leaving just feet.
Another note: if you want, think of the 44 as -44 to indicate that the plane is decreasing at a rate of 44 ft/sec
Answer:
Here's a screenshot. Hope this helps
(x,y)
y does't change makes it easier
frm 7 to -2
-2-7=-9
distance is 9
Greetings from Brasil...
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Here's our problem:
From potentiation properties:
Mᵃ ÷ Mᵇ = Mᵃ⁻ᵇ
<em>division of power of the same base: I repeat the base and subtract the exponents</em>
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Bringing to our problem
12¹⁶ ÷ 12⁴
12¹⁶⁻⁴
<h2>12¹²</h2>
