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3 years ago

Help with this math question

Mathematics

2 answers:

marta [7]3 years ago

7 0

The given inequality is:

|-8x+24| \leq 16

This inequality can be divided in two parts as:

a) -16 \leq -8x +24

b) -8x + 24 \leq 16

Solving part a:

-16 \leq -8x+24 \\ \\ 
-40 \leq -8x \\ \\ 
5 \geq x \\ 
or \\ 
x \leq 5

Solving part b:

-8x+24 \leq 16 \\ \\ 
-8x \leq -8 \\ \\ 
x \geq 1

Therefore, the solution to the given inequality is x \leq 5 and x \geq 1. Combining both the ranges we get the solution: 1 \leq x \leq 5.

In interval notation, this solution can be expressed as [1,5

Read more on Brainly.com - brainly.com/question/9377317#readmore

tresset_1 [31]3 years ago

3 0

The given inequality is:

$|-8x+24| \leq 16$

This inequality can be divided in two parts as:

a) $-16 \leq -8x +24$
b) $-8x + 24 \leq 16$

Solving part a:

$-16 \leq -8x+24 \\ \\ 
-40 \leq -8x \\ \\ 
5 \geq x \\ 
or \\ 
x \leq 5$

Solving part b:

$-8x+24 \leq 16 \\ \\ 
-8x \leq -8 \\ \\ 
x \geq 1$

Therefore, the solution to the given inequality is $x \leq 5$ and $x \geq 1$ . Combining both the ranges we get the solution: $1 \leq x \leq 5$ .

In interval notation, this solution can be expressed as [1,5]

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Find the nth term of the geometric sequence whose initial term is a1

Alborosie

Answer:

Step-by-step explanation:

geometric progresion formula:

$a_n=a_1*r^{n-1}\\a_1=0.5\\r=10\\a_n=0.5*10^{n-1}$

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2 years ago

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

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3 years ago

Question in the image please help!!

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Answer: 300

Explanation: $13.00 x 20 + 40 I think

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2 years ago

Everett, Miguel, and Ramona are partners, sharing income 1:2:3. After selling all of the assets for cash, dividing losses on rea

andreev551 [17]

The amount of cash available for distribution to the partners is <u>$46,000</u>.

<h3>How is the amount of cash determined?</h3>

The amount of cash available for distribution to the partners is computed by summing the partners' capital balances.

From the scenario, Miguel owes the partnership $45,500. Since Miguel has not brought in this amount, the cash available for now is $46,000.

If Miguel cannot bring in $45,500, it implies that the other two partners will share the loss in their income-sharing ratio before distributing the remaining cash.

<h3>Data and Calculations:</h3>

Partners = Everett, Miguel, and Ramona

Income-sharing ratio = 1:2:3

Capital account balances:

Everett, $53,600 Cr.

Miguel, $45,500 Dr.

Ramona, $37,900 Cr.

Total = $46,000 CR

Thus, the amount of cash available for distribution to the partners is <u>$46,000</u>.

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Step-by-step explanation:

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3 years ago