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Trava [24]
2 years ago
9

PLEASE HELP!!

Mathematics
2 answers:
aliya0001 [1]2 years ago
8 0
97% is the score Olivia can get hop this helps
UNO [17]2 years ago
8 0

Answer:

97%

Step-by-step explanation:

89%+98%+96%+?=95×4

283+?=380

?=380-283

?=97%

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Guys please do awser this for me :(
xxTIMURxx [149]

Answer:

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Step-by-step explanation:

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3 years ago
2.548 rounded to the number 2.55 which place value did Marco round to
JulijaS [17]
The tens place because 4 and 8, 8 is over 5 so u round up then it is 254 rounded to the tens 55
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3 years ago
Read 2 more answers
Plz solve the following with steps (people who just come by without answering the question and taking the points may end up as b
sleet_krkn [62]

Answer:

<h2>12) There are 534 students who do not lunch in school.</h2>

Step-by-step explanation:

<h3>12. </h3><h3>Simple solution: </h3><h3>890 ÷ 5 = 178 </h3><h3>Therefore: 1/5 = 178 </h3><h3 /><h3>•To find the 2/5 of the students, we have to multiply 178 by 2</h3><h3>178 × 2 = 356</h3><h3>Therefore, 356 students stay to have lunch.</h3><h3 /><h3>•To find the remaining students who do not lunch in school, we have to subtract 356 to 890.</h3><h3>890 - 356 = 534</h3><h3>Therefore, there are 534 students who do not lunch in school.</h3><h3 /><h3 />
8 0
3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
2 years ago
Jevon arrives home from school at 3:10.it takes him 15 minutes to eat a snack 1/2 hour to complete his homework 7 minutes to cha
zysi [14]
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