Answer:
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
Step-by-step explanation: See Annex
Green Theorem establishes:
∫C ( Mdx + Ndy ) = ∫∫R ( δN/dx - δM/dy ) dA
Then
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy
Here
M = 2x + cosy² δM/dy = 1
N = y + e√x δN/dx = 2
δN/dx - δM/dy = 2 - 1 = 1
∫∫(R) dxdy ∫∫ dxdy
Now integration limits ( see Annex)
dy is from x = y² then y = √x to y = x² and for dx
dx is from 0 to 1 then
∫ dy = y | √x ; x² ∫dy = x² - √x
And
∫₀¹ ( x² - √x ) dx = x³/3 - 2/3 √x |₀¹ = 1/3 - 0
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
The largest number is 345
Using the probability concept, it is found that since the number of red sweets would be a decimal number, the probability cannot be 
<h3>What is probability?</h3>
Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
In this problem:
- In total, there are 8 + n sweets in the bag.
The probability of red is:
Supposing, we solve for n:
10n = 7n + 56
3n = 56
n = 56 / 3
n = 18.67
Since the number of red sweets would be a decimal number, the probability cannot be 7 / 10
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Answer:
78.5
Step-by-step explanation:
area of a circle is 
3.14(
)=78.5
Answer:
155
Step-by-step explanation:
