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3 years ago

Can someone please help me?

Mathematics

2 answers:

Nastasia [14]3 years ago

7 0

The answer is

X = -1 or x = 3

Mumz [18]3 years ago

3 0

The answer is 2 kcjfjc

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PLEASE HELP ASAP <br>are f(x)=4/x-2-1 and g(x)=3/x+2-2 inverses of each other?

GREYUIT [131]

Answer:

To find the inverse of:

$f (x)=\dfrac{4}{x-2}-1$

Set the function to y:

$\implies y=\dfrac{4}{x-2}-1$

Rearrange to make x the subject:

$\implies y+1=\dfrac{4}{x-2}$

$\implies (y+1)(x-2)=4$

$\implies xy-2y+x-2=4$

$\implies xy+x=2y+6$

$\implies x(y+1)=2y+6$

$\implies x=\dfrac{2y+6}{y+1}$

Swap x and y:

$\implies y=\dfrac{2x+6}{x+1}$

Change y to the inverse of the function sign:

$\implies f$ $\:^{-1}(x)=\dfrac{2x+6}{x+1}$

Rewrite g(x) as a fraction:

$g(x)=\dfrac{3}{x+2}-2$

$\implies g(x)=\dfrac{3}{x+2}-\dfrac{2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2x-4}{x+2}$

$\implies g(x)=-\dfrac{2x+1}{x+2}$

Therefore, as the inverse of f(x) ≠ g(x), the functions are NOT inverses of each other

4 0

2 years ago

Which expression is equivalent to ?

mamaluj [8]

Answer:

Step-by-step explanation:

$\frac{(a^{2}b^{4}c)^{2}*(6a^{3}b)*(2c^{5})^{3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{2*2}b^{4*2}c^{2}6a^{3}b2^{3}c^{5*3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{4}b^{8}c^{2}6a^{3}b8c^{15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*8*a^{4+3}b^{8+1}c^{2+15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*2*a^{7}b^{9}c^{17}}{a^{6}b^{12}c{^3}}\\\\=\frac{12a^{7-6}c{17-3}}{b^{12-9}}\\\\=\frac{12a^{1}c^{14}}{b^{3}}\\\\=\frac{12ac^{14}}{b^{3}}$