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4 years ago

12

A 1700kg rhino charges at a speed of 50.0km/h. What is the magnitude of the average force needed to bring the rhino to a stop in

0.50s?

1 answer:

Ksivusya [100]4 years ago

7 0

Force (N) = mass (kg) x velocity (m/s) / time (s)

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A thin rod rotates at a constant angular speed. Consider the tangential speed of each point on the rod for the case when the axi

ASHA 777 [7]

Answer:

v = R w

With this expression we see that for each point at different radius the tangential velocity is different

Explanation:

They indicate that the angular velocity is constant, that is

w = dθ / dt

Where θ is the radius swept angle and t the time taken.

The tangential velocity is linear or

v = dx / dt

Where x is the distance traveled in time (t)

In the definition of radians

θ = s / R

Where s is the arc traveled and R the radius vector from the pivot point, if the angle is small the arc (s) and the length (x) are almost equal

θ = x / R

We substitute in the speed equation

v = d (θ R) / dt

The radius is a constant for each point

v = R dθ / dt

v = R w

With this expression we see that for each point at different radius the tangential velocity is different

6 0

3 years ago

An 80 kg hockey player is skating at 4.1 m/s when an 85 kg hockey player from

atroni [7]

Answer:

ygubh

Explanation:

bgubgyu

6 0

3 years ago

A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle ϕ=30∘ above the horizontal, as shown (Figure

Nesterboy [21]

Answer:

<h2>The work done is 0.882 Joules.</h2>

Explanation:

To calculate the work, we need to find all forces that are involved in the movement.

As you can analyse, the body is the force that make the box to move, and the friction force is opposite to it, we cannot forget about the friction. So, we have to calculate the resultant force to this context.

$F_{R}=W_{x}-F_{k}$

So, to find $W_{x}$ we use: $W_{x}=W.sen\phi$ ; where $W=2N;\phi = 30\°$

$W_{x}=2N.sin30\°=1\frac{1}{2}N=1N$

The friction force would be:

$F_{k}=\mu_{k}N=(0.30)(1.7N)=0.51$

Then, the resultant force is:

$F_{R}=W_{x}-F_{k}$

$F_{R}=1N-0.51N=0.49N$

Now, we calculate the work: $W=F_{R} d$

$W=(0.49N)(1.8m)=0.882J$

Therefore, the work done is 0.882 Joules.

7 0

4 years ago

Read 2 more answers

What is the voltage if the current is 4 A and the resistance is 10 Ω?

ZanzabumX [31]

Answer:

40 volts

Explanation:

Use the equation $V=IR$

$V=(4)(10)$

$V=40$

5 0

3 years ago

A car of mass 1200 kg is traveling at 2 m/s. Then it collides with a heavy boulder in the road. During the collision, the car mo

olga2289 [7]

Answer:

F = 1.6*10⁴ N

Explanation:

Given distance x = 0.15m, mass m = 1200kg, velocity v = 2m/s.

Unknown: force F

Force is given by Newton's law:

(1) $F = ma$

The average force to stop an object from a velocity will be the same force necessary to accelerate an object from rest to the same velocity.

The distance for an object starting from rest for a constant acceleration is given by:

(2) $x=\frac{1}{2}at^2$

The velocity for an object starting from rest for a constant acceleration:

(3) $v=at$

Using equation 2 and 3 to eliminate time t:

(4) $x=\frac{1}{2}a\frac{v^2}{a^2}=\frac{v^2}{2a}$

Solving equation 4 for the acceleration a:

(5) $a=\frac{v^2}{2x}$

Using equation1 to solve for the force F:

(6) $F=ma=\frac{mv^2}{2x}$

4 0

4 years ago