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VladimirAG [237]
3 years ago
12

Which of the following could be possible vector directions

Physics
1 answer:
blsea [12.9K]3 years ago
5 0

A vector in a given plane can have any direction

In XY plane we can say that its direction is

North = + Y direction

South = - Y direction

East = + X direction

West = - X direction

so all of the above directions can be considered as direction of a given vector as a vector can incline in all above direction as well and at any angle with all also

so here it is also possible to have a direction which is along 45 degree North of East which will incline between X and Y direction both

So here all four options may be the possible direction of a vector

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A string is attached to a ball that has a mass of 0.11 kg. A student pulls up on the string so that the ball accelerates upward
enot [183]

Answer:

T=+1.133N

Explanation:

Tension and weight are forces that have opposite directions

Weight is negative (downward)

W=m*g= 0.11kg*(-9.8m/s^2)

W= -1.078N

Tension is possitive (upward)

The total force will be the sum of both (the difference taking in consideration the direction)

Ft= T+W

Also the total force is the product of the mass due to acceleration:

Ft=m*a

Ft= +0.11kg*0.5m/s^2

Ft=+0.055N (upward)

Tension will be the difference between Ft and W:

T= Ft-W

T=+0.055N-(-1.078N)

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In the sum A→+B→=C→, vector A→ has a magnitude of 13.6 m and is angled 40.2° counterclockwise from the +x direction, and vector
il63 [147K]

Answer:

|B|=27.00425726m

\alpha =210.3781372°

Explanation:

Let's use the component method of vector addition:

A_x=13.6cos(40.2)=10.38762599\\A_y=13.6sin(40.2)=8.778224553\\Cx=13.8cos(20.7+180)=-12.90912763\\Cy=13.8sin(20.7+180)=-4.877952844

Now, we know:

C_x=A_x+B_x\\\\C_y=A_y+b_y

So:

B_x=C_x-A_x=-23.29675362\\B_y=C_y-A_y=-13.6561774

Now lets calculate the magnitude of the vector B:

|B|=\sqrt{(B_x)^{2} +(B_y)^{2}  }=27.00425726m

Finally its angle is given by:

\alpha =(arctan(\frac{B_y}{B_x}))+180=30.37813438+180=210.3781344°

Keep in mind that I added 180 to the angles of C and B to find the real angles measured from the + x axis counter-clock wise.

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