1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inn [45]
3 years ago
7

A thin rod rotates at a constant angular speed. Consider the tangential speed of each point on the rod for the case when the axi

s of rotation is perpendicular to the rod at its center and at one end. Explain for each case whether there are any points on the rod that have the same tangential speeds.
Physics
1 answer:
ASHA 777 [7]3 years ago
6 0

Answer:

    v = R w    

With this expression we see that for each point at different radius the tangential velocity is different

Explanation:

They indicate that the angular velocity is constant, that is

            w = dθ / dt

Where θ is the radius swept angle and t the time taken.

The tangential velocity is linear or

           v = dx / dt

Where x is the distance traveled in time (t)

 

In the definition of radians

          θ = s / R

Where s is the arc traveled and R the radius vector from the pivot point, if the angle is small the arc (s) and the length (x) are almost equal

         θ = x / R

We substitute in the speed equation

         v = d (θ R) / dt

The radius is a constant for each point

         v = R dθ / dt

         v = R w

With this expression we see that for each point at different radius the tangential velocity is different

You might be interested in
A 0.280 m radius, 475 turn coil is rotated one-fourth of a revolution in 4.17 ms, originally having its plane perpendicular to a
KonstantinChe [14]
Hope it helps u mate. Plz follow me .

8 0
4 years ago
Which information about the earth would not be represented when a globe is used as a model?
egoroff_w [7]
A globe sitting on the desk can't demonstrate the speed of axial rotation
or the speed of orbital revolution.
5 0
3 years ago
Electricity from the local power company costs 7.22 cents/kWh. A homeowner wishes to pay a maximum of 25 cents per month for the
mestny [16]
You haven't said how much power the stereo uses.  It matters !

Whatever that number is, the maximum hours per month is

    (3460) divided by (the # of watts the stereo uses when it's playing) .
7 0
3 years ago
Read 2 more answers
When the cylinder is displaced slightly along its vertical axis it will oscillate about its equilibrium position with a frequenc
Nesterboy [21]

Answer:

w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

Explanation:

We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is

          w² = mg d / I

In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow

         d = L / 2

The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated

        I = ¼ m r2 + ⅓ m L2

        I = m (¼ r2 + ⅓ L2)

now let's use the concept of density to calculate the mass of the system

        ρ = m / V

        m = ρ V

the volume of a cylinder is

         V = π r² L

          m =  ρ π r² L

let's substitute

        w² = m g (L / 2) / m (¼ r² + ⅓ L²)

        w² = g L / (½ r² + 2/3 L²)

        L >> r

         w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

4 0
4 years ago
The Great Sandini is a 60 kg circus performer who is shotfrom a cannon (actually a spring gun). You don't find many men ofhis ca
d1i1m1o1n [39]

Answer:

V=15.3 m/s

Explanation:

To solve this problem, we have to use the energy conservation theorem:

U_e+K_i+U_{gi}+W_{friction}=K_f+U_{gf}

the elastic potencial energy is given by:

U_e=\frac{1}{2}*k*x^2\\U_e=\frac{1}{2}*1100N/m*(4m)^2\\U_e=8800J

The work is defined as:

W_{friction}=F_f*d*cos(\theta)\\W_{friction}=40N*2.5m*cos(180)\\W_{friction}=-100J

this work is negative because is opposite to the movement.

The gravitational potencial energy at 2.5 m aboves is given by:

U_{gf}=m*g*h\\U_{gf}=60kg*9.8*2.5\\U_{gf}=1470J

the gravitational potential energy at the ground and the kinetic energy at the begining are 0.

8800J+0+0+-100J=\frac{1}{2}*62kg*v^2+1470J\\v=\sqrt{\frac{2(8800J-100J-1470J)}{62kg}}\\v=15.3m/s

3 0
3 years ago
Other questions:
  • A square coil (length of side = 24 cm) of wire consisting of two turns is placed in a uniform magnetic field that makes an angle
    15·1 answer
  • if spiderman runs and jumps horizontally from the top of a 200m high building, what does he need his velocity to be to land on a
    5·1 answer
  • When the point of reference (the observer) is in motion, it flips the "rules" of vector addition (you ADD the vectors going in o
    14·1 answer
  • a rock with mass of 5kg is carried up a small hill 10 meters high. how much work had to be done in carrying the rock up hill
    8·1 answer
  • How come that there is a presence of cos there?
    8·1 answer
  • A constant force of 5KN pulls a crate along a distance of 15 m in 75s.What is the power​
    6·1 answer
  • Describe the field that is being created in the above experiment.
    15·2 answers
  • A laborer pushes a box to distance of 20m. if the force required to push the box is 25N what will be the quantity of work done​
    9·1 answer
  • Horizontal displacement?
    7·1 answer
  • Two male rabbits live in a habitat together. They both compete for mates and territory during the spring months. This is an exam
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!