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inn [45]
3 years ago
7

A thin rod rotates at a constant angular speed. Consider the tangential speed of each point on the rod for the case when the axi

s of rotation is perpendicular to the rod at its center and at one end. Explain for each case whether there are any points on the rod that have the same tangential speeds.
Physics
1 answer:
ASHA 777 [7]3 years ago
6 0

Answer:

    v = R w    

With this expression we see that for each point at different radius the tangential velocity is different

Explanation:

They indicate that the angular velocity is constant, that is

            w = dθ / dt

Where θ is the radius swept angle and t the time taken.

The tangential velocity is linear or

           v = dx / dt

Where x is the distance traveled in time (t)

 

In the definition of radians

          θ = s / R

Where s is the arc traveled and R the radius vector from the pivot point, if the angle is small the arc (s) and the length (x) are almost equal

         θ = x / R

We substitute in the speed equation

         v = d (θ R) / dt

The radius is a constant for each point

         v = R dθ / dt

         v = R w

With this expression we see that for each point at different radius the tangential velocity is different

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Explanation:

The confidence interval for population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

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Sample mean : \ovreline{x}=50.3\text{ decibels}

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How high would the level be in a gasoline barometer at normal atmospheric pressure?
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Answer:

h = 13.06 m

Explanation:

Given:

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- The atmosphere pressure P_o = 101.325 KPa

- The change in height of the liquid is h m

Find:

How high would the level be in a gasoline barometer at normal atmospheric pressure?

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- When we consider a barometer setup. We dip the open mouth of an inverted test tube into a pool of fluid. Due to the pressure acting on the free surface of the pool, the fluid starts to rise into the test-tube to a height h.

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Where,                              h = P / S.G*p_w*g

- Input the values given:

                                         h = 101.325 KPa / 0.739*9.81*997

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- Hence, the gasoline will rise up to the height of 13.06 m under normal atmospheric conditions at sea level.

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