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Aleks04 [339]
3 years ago
13

I need these answers

Mathematics
1 answer:
Brut [27]3 years ago
4 0
I hve answered, what is your question?
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A square wall tile has an area of 58,000 square millimeters. Between which two measurements is the length of one side
scoray [572]

\bf \textit{area of a square}\\\\ A=s^2~~ \begin{cases} s=side's\\ \qquad length\\[-0.5em] \hrulefill\\ A=58000 \end{cases}\implies 58000=s^2\implies \sqrt{58000}=s \\\\\\ 240.83\approx s~\hspace{9em} \boxed{240}\rule[0.35em]{10em}{0.25pt}240.83\rule[0.35em]{1.7em}{0.25pt}\boxed{241}

6 0
3 years ago
April is randomly choosing five CDs to bring in her car from the following: 6 pop CDs, 8 rock CDs, and 10 R&B CDs. What is t
padilas [110]
The answer is B: <span>choosing five CDs where not all of them are pop</span>
7 0
3 years ago
Read 2 more answers
Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3​
maria [59]

Answer:

  (x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

  (2/x +1/y) -2(1/x -5/y) = (3) -2(7)

  11/y = -11 . . . . simplify

  y = -1 . . . . . . . multiply by y/-11

Using the second equation, we can find x:

  2/x +1/-1 = 3

  2/x = 4 . . . . . . . add 1

  x = 1/2 . . . . . . . multiply by x/4

The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

6 0
2 years ago
Tell me the answer to the question plz​
Sonja [21]

Step-by-step explanation:

(11.99+23.98+9.95)= 45.92

she has to pay = 45.92 - 20/100 (45.92)

= 45.92 - 9.18 = 36.74

so option

about 37 is right

4 0
3 years ago
Find S11 for 1 + 2 + 4 + 8 +
Free_Kalibri [48]
Evaluating the given sequence, it is evident that the next number is twice the number prior to it. Thus, the given is a geometric sequence with first term (a1) equal to 1 and common ratio of 2. The geometric series may be calculated by the equation,
 
                                            Sn = a1 x (1 - r^n) / (1 - r)

where Sn is the sum of n terms in this case, n = 11. 
Substituting the known values, 
 
<span>                                      Sn = 1 x (1 - 2^11) / (1 - 2) = 2047
</span>
Thus, S11 is 2047. 
4 0
3 years ago
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