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2 years ago

WORTH 10 POINTS! PLZZZ ANSWEEERRRR!!111

2 answers:

7 0

A) 2, because to find the interquartile range, you need to find the median of the upper and lower quartiles. Then, subtract the lower quartile from the upper quartile. There is the interquartile range.

Juli2301 [7.4K]2 years ago

6 0

The interquartile range is 12-6=6

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Maria makes $2,500 per month. What is the maximum amount of rent she can afford?

Gnom [1K]

Answer:

800

Step-by-step explanation:

5 0

2 years ago

23.96448 to the nearest tenth

Ulleksa [173]

The answer is 24 this needs to be longer so it will send

8 0

2 years ago

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A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

2 years ago

What is triple of 1/2 oranges on a recipe?

Elena-2011 [213]

It is 1 and 1\2 oranges hope this helps!!

4 0

3 years ago

Read 2 more answers

Help Me Pls Thanks <3

dybincka [34]

If there are 150 total instruments in said Orchestra, we'll need to divide that number in half.
75, simple enough. Now we know that half of 150 is 75.
Start by writing your problem like this: 150= 75w+37.5b
That equation is all I can think of, because 37.5 is half of 75, which means that's roughly the number you're looking for. Sorry if this doesn't help much<span />

8 0

2 years ago