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nika2105 [10]
3 years ago
12

WORTH 10 POINTS! PLZZZ ANSWEEERRRR!!111

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0
A) 2, because to find the interquartile range, you need to find the median of the upper and lower quartiles. Then, subtract the lower quartile from the upper quartile. There is the interquartile range.
Juli2301 [7.4K]3 years ago
6 0
The interquartile range is 12-6=6
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36√(3)-(432/7+4√(3))=?
Elden [556K]
40√3+432/7 is the answer

Hope this helps :D
5 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
Can some one please help me with this??
mart [117]
2.

0.05 miles

3.

a

4.

a

5.

1 Book for ever 10$

6.

28 MPH



Thats it!
Hope this helps
7 0
3 years ago
A sports club is holding a fundraiser dinner. The function graphed models the profit, y, in dollars, from selling x tickets.
Ymorist [56]
1. true 2. false 3.true
7 0
2 years ago
Read 2 more answers
Two computer disks and three notebooks cost $17. However,
zhuklara [117]

Answer:

Computer disks are $4 each

Notebooks are $3 each

Step-by-step explanation:

For the first equation

<em>$4 x 2 disks = $8</em>

<em>$3 x 3 notebooks = $9</em>

<em>$9 + $8 = </em>$17

For the second equation

<em>$4 x 5 disks = $20</em>

<em>$3 x 4 notebooks = $12</em>

<em>$20 + $12 = </em>$32

3 0
3 years ago
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