Answer:
1 stack of 60
2 stacks of 30
3 stacks of 20
4 stacks of 15
5 stacks of 12
6 stacks of 10
60 stacks of 1
30 stacks of 2
20 stacks of 3
15 stacks of 4
12 stacks of 5
Prime Factorisation
Step-by-step explanation:
To find the number of stacks you can make just divide the total by the size of the stacks. This also works in reverse.
To find the prime factorisation you just find the factors of the number by dividing it by the largest prime possible.
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
We only see the Moon because sunlight reflects back to us from its surface. But the the lit side does not always face the Earth. As the moon circles the Earth, the amount of the lit side we see changes.
3/5 / 3/7
= 3/5 * 7/3
= 7/5 or 1 2/7
Answer:
Step-by-step explanation:
Here you go! If you have more like these I recommend using Desmos Graphing calculator :)
