Answer:
On your desktop, hover over the message you'd like to share and click the Share message icon on the right. Use the drop-down menu to choose where you'd like to share the message, and add a note if you'd like. Click Share to see the message expand.
Explanation:
Answer:
A security utility program that scans the system for small programs that interfere with how a computer functions are _____ utilities.
Explanation:
The option that is true for the Student Version above is option d: This is not plagiarism.
<h3>What is
plagiarism?</h3>
This is known to be the act of copying other people's work and then taking it as your own.
When you look at the student work, you will see some measures od differences. Hence, The option that is true for the Student Version above is option d: This is not plagiarism.
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See full question below
Original Source Material
There is a design methodology called rapid prototyping, which has been used successfully in software engineering. Given similarities between software design and instructional design, we argue that rapid prototyping is a viable method for instructional design, especially for computer-based instruction.
Student Version
Rapid prototyping could be an advantageous methodology for developing innovative computer-based instruction. Software engineers have been successful in designing applications by using rapid prototyping. So it also could be an efficient way to do instructional design.
Which of the following is true for the Student Version above?
a. Word-for-Word plagiarism
b. Paraphrasing plagiarism
c. This is not plagiarism
Answer:
Following are the solution to the given choices:
Explanation:
Given:
double currentBalance[91];//defining a double array
In point a:
The name of the array is= currentBalance.
In point b:
91 double values could be saved in the array. It requires 8bytes to hold a double that if the array size is 91*8 = 728
In point c:
Each element's data type is double.
In point d:
The array index range of values is between 0 and 90 (every array index starts from 0 and ends in N-1, here N=91).
In point e:
To access first element use currentBalance[0], for middle currentBalance[91/2] , for last currentBalance[90]
