Identical objects are placed in Beaker A and in Beaker B. The objects float as shown in the diagrams below. What can you conclud
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Answer:
A) The algorithm will work if they are divided into groups of 7
B ) If the groups of 3 are used they do not run in Linear time
Explanation:
ATTACHED TO THIS IS THE DETAILED PROVE OF why the algorithm will work if they are divided into groups of 7 and also the prove that if groups of 3 are used they do not run in Linear time
