Answer:
Anaphase II.
Explanation:
Cell division may be defied as the phenomena by which the cell multiply and increases its number under the influence of cell cycle checkpoints. Two main type of cell division are meiosis and mitosis.
The meiosis result in the formation of four haploid cells from the single parent diploid cell. The Anaphase II of meiosis leads to the disjoin of the sister chromatids and the separation of chromatids. This is similar to the anaphase of mitosis.
Thus, the correct answer is anaphase II.
Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
determined by genetic factors and therefore able to be passed on from parents to their offspring or descendants.
The answer is D. a push the acts over a certain area.
The muscular system allows the body to move while the skeletal system provides a structure and form to our body. Without the muscular system we could not move and without the skeletal system we would not take any form.
Hope this helped!
