Answer:
See below
Step-by-step explanation:

The fraction of a defective item getting by both inspectors is
= 
Step-by-step explanation:
Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).
Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.
P(A) = 0.1 =
.
It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) =
.
Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.
P(A and B happening) = P(A) × P(B) =
×
=
=
= 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.
Hi I am here to help :). I think the answer would be 7/4. Good luck!
The answer is C because AO and BO are equal. And with AO being three times the length of CO, BO should be the length of DO
Answer:
A. (x*2.5)*x
B. (32*2.5)*32=2560
Step-by-step explanation: