If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
Answer:
A) 
B) 
C) 
Step-by-step explanation:
Given the exponential expression, 
:
A) is equivalent to due to the Product Rule of exponents: 
.
Next, apply the Power-to-Power Rule of exponents: 
.
B) is equivalent to due to the Power-to-Power Rule of exponents: .
.
C) is equivalent to due to the Product-to-Power Rule of exponents: 
.
So x equals two if it is an exponent.9
