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3 years ago

-7x+7y=-28 -3x-4y=-12

Mathematics

1 answer:

gtnhenbr [62]3 years ago

8 0

Answer:

<h2>hope it helps you see the attachment for further information ✌✌✌✌✌</h2>

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There are about 1.5 grams of fat in 1 tablespoon of hummus. How many grams of fat are in 2 1/2 cups of hummus? ( Note: 16. Table

grin007 [14]

2 and 1/2=2.5cups
2.5 times 16=40tablespoons

1.5g=1tbs
1.5 times 40=60
60 grams

8 0

4 years ago

Read 2 more answers

I need help with this

Fudgin [204]

You can’t solve this, not enough information

5 0

4 years ago

.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and

Leni [432]

Answer:

a) Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

b) $t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

Step-by-step explanation:

Information given

$\bar X=130$ represent the sample mean for the amount spent each shopper

$s=40$ represent the sample standard deviation

$n=80$ sample size

$\mu_o =120$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

The statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

5 0

4 years ago

A business uses straight-line depreciation to determine the value y of an automobile over a 5-year period. Suppose the original

Elena-2011 [213]

For this problem. it is found that:

a) The automobile has depreciated 75% in 5 years.

b) The value of the automobile was reduced by $10,500 in five years.

c) The linear function is: s(t) = 14,500 - 2,100t.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = ax + b

In which:

a is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

From the problem, we have that:

a) The automobile has depreciated 75% in 5 years, as 4000/14500 = 0.25, and 100% - 25% = 75%.

b) The value of the automobile was reduced by $10,500 in five years, as 14500 - 4000 = $10,500.

For the linear function, we have that:

The initial value is b = 14500.

The slope is of a = -10500/5 = -2100.

Hence the linear function is: s(t) = 14,500 - 2,100t.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

6 0

2 years ago

Given the following table, determine the missing value.

sergeinik [125]

We know that
Based on the table
Percent%=[1-Decay factor]*100%
so

for decay factor=0.98
Percent%=[1-0.98]*100%----> 2%

for decay factor=0.50
Percent%=[1-0.50]*100%---->50 %

for decay factor=0.64
Percent%=[1-0.64]*100%----> 36%

for decay factor=0.23
Percent%=[1-0.23]*100%----> 77%

therefore

the answer is
36%

6 0

3 years ago