The carbon 14 left from this animal is 3 grams of 24 grams which is: 3g/24g= 1/8 times of its original mass. Then, the age of the animal fossil would be:
final weight= initial weight * (1/2) ^ time/half-live
1/8 initial weight = initial weight * (1/2) ^ time/half-live
log2 1/8= log2 (1/2) ^ time/half-live
-3= -time/half-live
time= -3 * -(half-live)
time= 3 half-live
If the half-live is 5730 years, the age would be: 3* 5730= 17.190 years.
Answer:
Your answer should be a. There is an increase in the number of collisions between particles and the walls of the container.
