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dem82 [27]
3 years ago
13

The coordinates of point A are (6;4). The coordinates of point B are (3;4). Which expression represents the distance, in units,

between points A and B?
Mathematics
1 answer:
Vlad [161]3 years ago
7 0

Answer:

that would be 3 units

Step-by-step explanation:

if they are on the same y line, 4, then the distance would be 3 6-3=3

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In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on th
Serggg [28]

Answer:

The weighted average is of 69.94.

Step-by-step explanation:

Weighted average:

The weighed average is found multiplying each grade by its respective weight.

The grades, and weights are:

67 on the lab, with a weight of 23% = 0.23

69 on the first major test, with a weight is 21.5% = 0.215

85 on the second major test, with a weight is 21.5% = 0.215.

63 on the final exam, with a weight of 34% = 0.34.

Weighted average:

A = 0.23*67 + 0.215*69 + 0.215*85 + 0.34*63 = 69.94

The weighted average is of 69.94.

8 0
3 years ago
If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s powe
vovangra [49]

Answer:

1.3\cdot 10^3\text{ J}

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

W=Fd, where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by F_g=mg, where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, F_g=75\cdot 9.8=735\text{ N}. Since she raises her body 4.0 meters, the work done must be W=Fd=735\cdot 4=2940\text{ J}.

Since power is equal to work over time and t = 2.3 seconds, we have:

\displaystyle P=\frac{W}{t}=\frac{2940}{2.3}=\boxed{1278\text{ J}}\approx \boxed{1.3\cdot 10^3\text{ J}} (to two significant figures)

7 0
2 years ago
mr richey bought 20 organizer books and 20 staplers for students. each stapler costs 3$. mr richey spent in total of 200$ for th
pantera1 [17]

Answer: $7

Step-by-step explanation: if a stapler cost $3, then 20staplers will cost $60

Amount left will be $200-60=$140

Cost of one organiser will be $140/20

That will be $7

4 0
2 years ago
Read 2 more answers
Solve for n <br>n+1 3/5 =3 3/10
RoseWind [281]
The answer is N=17/10
8 0
4 years ago
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