Find four consecutive integers such that if the sum of the first and third is increased by 10, the result is 6 greater than 4 ti
mes the fourth
1 answer:
Four consecutive integers are four numbers in a row, with a difference of one between each of them.
x= first integer
x+1= second integer
x+2= third integer
x+3= fourth integer
sum= add
increased by 10= add 10
the result is= equal sign
6 greater than= add 6
4 times= multiply
EQUATION
(x + x + 2) + 10= (4(x + 3)) + 6
combine like terms on the left side
2x + 12= (4(x + 3)) + 6
multiply 4 by terms in parentheses
2x + 12= 4x + 12 + 6
combine like terms on right side
2x + 12= 4x + 18
subtract 4x from both sides
-2x + 12= 18
subtract 12 from both sides
-2x= 6
divide both sides by -2
x= -3 first integer
x+1= -2 second integer
x+2= -1 third integer
x+3= 0 fourth integer
ANSWER: The four consecutive integers are -3, -2, -1 and 0.
Hope this helps! :)
You might be interested in
Answer:
30 and 36
Step-by-step explanation:
six times two equals 12
6 * 3 = 18
and six times four equals 24.
to get the next two multiples, You need to multiply 6 by 5, and then 6
6 * 5 = 30 and 6 * 6 = 36
Answer:
what do you want to know?
Step-by-step explanation:
Answer:
the other person is wrong, its b, d, e, and f
Step-by-step explanation:
Answer:
125 I think
Step-by-step explanation:
Multiply 30 x 3 then add 35
Hope it's right
Step-by-step explanation:
10×10+24×24= third side ×third side
third side ×third side =100+576
third side × third side=676
third side=√676
third side=26