We know that the peaches increase to 50 peaches, so we just need to take 50÷200=25%. As a result, the percent increase is 25%. Okay, let me emphasize this amount of increase means that the amount of increase from 200 peaches to 250 peaches is increasing 50 peaches. And the original price which is 200 peaches, so 25/200=0.25 or 25% as a percent increase. Hope it help!
The sample space is 22 words and out of it, 14 words are known to have meanings for the student. In the problem, we use 10 C8 + 10 C9 + 10 C10 to associate at least 8 words. The complete formula is (10 C8 * (14/22)^8 * (8/22)^2 + 10 C9 (14/22)^9 * (8/22)^1 + 10 C 10 (14/22)^10 * (8/22)^)0) that is equal to 0.233
Complete question:
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.
A) Find the mean and standard deviation for the number of girls in groups of 36 births.
B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.
C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?
Answer:
a) mean = 18
Standard deviation =3
b) low range = 12
High range = 24
c) The result of 33 girls is significantly high. Yes, the method is effective.
Step-by-step explanation:
Given:
p = 0.5
n = 36
a) The mean is the product of n and p
Mean u = np
u = 36 * 0.5 = 18
The standard deviation is the square root of the product of n and p&q.
S.d ó = 


b) To find the range rule of thumb:
• For low range
Low range = u - 2ó
= 18 - (2 * 3)
= 12
• High range
= u + 2ó
= 18 + (2*3)
= 24
c) The result is significantly high, because 33 is greater than 24 girls.
A result of 33 girls would prove the method as effective.
Answer:
∠ EFG = 83°, ∠ GCE = 97°
Step-by-step explanation:
Since FE and FG are tangents to the circle then
∠ FGC and ∠ FEC are right angles
The sum of the angles in quadrilateral CEFG = 360°
Sum the 4 angles and equate to 360
3x + 11 + 90 + 5x - 23 + 90 = 360, that is
8x + 168 = 360 ( subtract 168 from both sides )
8x = 192 ( divide both sides by 8 )
x = 24
Thus
∠ EFG = 3x + 11 = 3(24) + 11 = 72 + 11 = 83°
∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°