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Tema [17]
3 years ago
12

Which equation describes the same line as y- 6 = -4(x + 1)?

Mathematics
2 answers:
just olya [345]3 years ago
8 0

Answer:

B. y=-4x+2

Step-by-step explanation:

y-6=-4x-4

y=-4x-4+6

y=-4x+2

NemiM [27]3 years ago
3 0
The answer is B. y= -4x+ 2
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How do you solve f-3/4=5/6?
gulaghasi [49]

Answer:

f =38

Step-by-step explanation:

f-3/4=5/6

f-3×6=5×4

f-18 =20

f =20+18

f =38

6 0
2 years ago
1+1 then divide by 8
Gemiola [76]

Answer:

0.25

Step-by-step explanation:

4 0
2 years ago
What does the equation 7x^2-3y^2-x+2y+4=0 represent
Romashka [77]

Answer:

Circle

Step-by-step explanation:

because a hyper bole is (y-k) 2b2 -(x-h) 2a2=1

ellipse is = (x-h) 2a2 + (y-k) 2b2 = 1

parabola is y= a (x-h) 2+ k

that's why circle is the answer

8 0
2 years ago
Which formula gives the x-coordinates of the maximum values for y = cos(x)?
solong [7]

We have been given a function y=\cos(x). We are asked to find the formula which gives the x-coordinates of the maximum values for given function.

We know that cosine function oscillates between -1 and 1 that is minimum value of cosine is -1 and maximum value is 1.

We also know that \cos(0)=1 and after period of cosine is 2\pi. This means after every 2\pi, we will get to 1.

So maximum of cosine is 2\pi n, where n is an integer.

Therefore, our required formula is 2\pi n, where, n=0,\pm 1,\pm 2,\pm3,...

7 0
3 years ago
For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm
Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

(\frac{14 \ mm}{7 \ mm})^{2}

= \frac{196 \ mm^{2} }{49\ mm^{2} }

=\frac{4}{1}

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0
2 years ago
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