Given :
A 2.8 m ladder is to be laid against a wall so that the top of the ladder is 2 m up the wall.
To Find :
How far out from the base of the wall should the ladder be placed.
Solution :
We know, the angle between floor and height is 90° .
Now, length of ladder, l = 2.8 m .
Height of wall, h = 2 m .
Let, distance between base of the wall and ladder is b .
Hence, this is the required solution.
Answer: 408 sq ft
Step-by-step explanation: You would need to use the surface area formula SA = 1/2LP + B. Note that L is the slant height, P is the perimeter of the base, and B is the area of the base. 11 is the slant height as shown in the image above, p is 48 since you add 12 + 12 + 12 + 12, and the area of the square will be 144 since 12*12 = 144. Once you substitute the numbers in their correct place, you should get SA = 1/2 (11)(48)+144 which gives you 408 sq ft. Hope this helps!
