Question

Solve.

Answer 1

Answer:

The solution is (4, 1).

Step-by-step explanation:

Our system is

$\left \{ {{2d-e=7} \atop {d+e=5}} \right.$

Since the coefficients of e are the same, we will add the two equations together to cancel it:

$\left \{ {{2d-e=7} \atop {+(d+e=5)}} \right. \\\\3d=12$

Divide both sides by 3:

3d/3 = 12/3

d = 4

Substitute this into the second equation:

4+e=5

Subtract 4 from each side:

4+e-4=5-4

e = 1

This makes the point (4, 1).

Answer 2

.hello : 
2d−e=7....(1)
d+e=5.....(2)
(1)+(2) : 3d=12
d=4
subsct in (2) : 
4+e=5
e=1
conclusion : 
The solution is (4, 1).