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Stolb23 [73]
3 years ago
15

Solve.

Mathematics
2 answers:
drek231 [11]3 years ago
5 0

Answer:

The solution is (4, 1).

Step-by-step explanation:

Our system is

\left \{ {{2d-e=7} \atop {d+e=5}} \right.

Since the coefficients of e are the same, we will add the two equations together to cancel it:

\left \{ {{2d-e=7} \atop {+(d+e=5)}} \right. \\\\3d=12

Divide both sides by 3:

3d/3 = 12/3

d = 4

Substitute this into the second equation:

4+e=5

Subtract 4 from each side:

4+e-4=5-4

e = 1

This makes the point (4, 1).

horrorfan [7]3 years ago
4 0
.hello : 
<span>2d−e=7....(1)
d+e=5.....(2)
(1)+(2) : 3d=12
d=4
subsct in (2) : 
4+e=5
e=1
conclusion : 
</span><span>The solution is (4, 1).</span><span>

</span>
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===========================================================

Explanation:

1/3 converts to the decimal form 0.333333... where the 3's go on forever

5/3 is a similar story but 5/3 = 1.666666.... where the '6's go on forever

The notation 0.\overline{6} indicates that the 6's go on forever.

So, 0.\overline{6} = 0.666666\ldots

The horizontal bar tells us which digits repeat. As another example, 0.\overline{123} = 0.123123123123\ldots

The three dots just mean "keep this pattern going forever".

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Everything mentioned so far has the decimal portions go on forever repeating some pattern over and over.

The only one that doesn't do this is 33% which converts to the decimal form 0.33

The value 0.33 is considered a terminating decimal since "terminate" means "stop". So this is the value that doesn't fit in with the other three items mentioned.

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