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qaws [65]
3 years ago
10

Find the slope of the line passing through the points (-6,-5) and (4,4)

Mathematics
1 answer:
marshall27 [118]3 years ago
3 0

Answer:

\frac{9}{10}

Step-by-step explanation:

The slope formula is  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Here, x_{1} is -6, x_{2} is 4, y_{1} is -5, and y_{2} is 4.

m=\frac{4+5}{4+6}

m=\frac{9}{10}

So, the slope of the line passing through the points (-6,-5) and (4,4) is \frac{9}{10}.

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Find the product of (4x − 3)(2x2 − 7x 1). 8x3 − 22x2 17x− 3 8x3 8x2 4x − 3 8x3 − 34x2 25x − 3 8x3 − 42x2 25x − 3.
Andrej [43]

Product of two polynomials can be done by distribution of multiplication over addition. The product of  (4x -3)(2x^2 -7x + 1) is 8x^3 - 34x^2 + 25x - 3

<h3>What is distributive property of multiplication over addition?</h3>

Suppose a, b and c are three numbers. Then we have:

a(b + c) = a\times b + a\times c

(a(b+c) means a multiplied to (b+c). The sign of multiplication is usually hidden when using symbols and both quantities which are in multiplication are written together without space)

The product result of the given expression is obtained as:

(4x -3)(2x^2 -7x + 1) = 4x(2x^2 - 7x + 1) -3(2x^2 - 7x + 1)\\(4x -3)(2x^2 -7x + 1) = 8x^{1 + 2} - 28x^2 + 4x - 6x^2 + 21x - 3\\(4x -3)(2x^2 -7x + 1) = 8x^3 + (-28-6)x^2 + (4 + 21)x - 3\\(4x -3)(2x^2 -7x + 1) = 8x^3 - 34x^2 + 25x - 3

Thus,

The product of  (4x -3)(2x^2 -7x + 1) is 8x^3 - 34x^2 + 25x - 3

Learn more about polynomial product here;

brainly.com/question/9106484

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