Let P be the population proportion, p be the sample proportion, n be the sample size.
A manufacturer claims that fewer than 6% of its fax machines are defective. It means P=0.06
Sample size n=97 and sample proportion p=0.05
The hypothesis to be tested is
H0: P ≥ 0.06 V/s Ha: P < 0.06
Here the hypothesis for testing population proportion we use z test statistics. Z test statistics is give by
Z = 
Where p =sample proportion = 0.05
p0 = hypothesized proportion value =0.06
Using given values into test statistics we get
Z = 
Z = -0.41
The p-value for left tailed alternative hypothesis is given by
P-value = P(z < z cal)
where zcal = Z test statistics value
Here zcal = -0.41
P-value = P(Z < -0.41)
Using z score table to find probability below z=-0.41
P-value = 0.3409
P-value for testing the given claim is 0.3409
4 significant figures.
Step-by-step explanation:
<h2>:)</h2>
Answer:
A
Step-by-step explanation:
The parabola ends at 4, and therefore the range is all real numbers under 4
Answer:
Solution
Step-by-step explanation:
If im wrong let me know okay!
If im wrong Im sorry Im only 15 and im working here to help
Answer:
zero goats and 120 Ilamas to get profit of $15,120
Step-by-step explanation:
Goats: G
Ilamas: l
Explicit constraints:
2G + 5l ≤ 400
100G+ 80l≤ 13,200
Implicit constraints
G≥0
I≥0
P= 84G+ 126l
See attachment for optimal area
substituting coordinats of optimal region in profit equation to get profit
When G= 132, l=0
P=84(132) + 126(0)
P=11,088
When G=0, l=120
P=84(0)+ 126(120)
P = 15120
When G= 100, l=40
P=84(100)+126(40)
P=13440