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fredd [130]
4 years ago
11

Is 2(x-y) and 2x-2y equivalent

Mathematics
1 answer:
julsineya [31]4 years ago
6 0

Answer:

Yes

Step-by-step explanation:

Start with the 2(x-y) and distribute the 2 to each term

2(x)-2(y)

This would equal

2x-2y

Which matches the second equation making the answer yes.

You might be interested in
a) What is an alternating series? An alternating series is a whose terms are__________ . (b) Under what conditions does an alter
andriy [413]

Answer:

a) An alternating series is a whose terms are alternately positive and negative

b) An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|, converges if 0< b_{n+1} \leq b_n for all n, and \lim_{n \to \infty} b_n = 0

c) The error involved in using the partial sum sn as an approximation to the total sum s is the remainder Rn = s − sn and the size of the error is bn + 1

Step-by-step explanation:

<em>Part a</em>

An Alternating series is an infinite series given on these three possible general forms given by:

\sum_{n=0}^{\infty} (-1)^{n} b_n

\sum_{n=0}^{\infty} (-1)^{n+1} b_n

\sum_{n=0}^{\infty} (-1)^{n-1} b_n

For all a_n >0, \forall n

The initial counter can be n=0 or n =1. Based on the pattern of the series the signs of the general terms alternately positive and negative.

<em>Part b</em>

An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|  converges if 0< b_{n+1} \leq b_n for all n and \lim_{n \to \infty} b_n =0

Is necessary that limit when n tends to infinity for the nth term of bn converges to 0, because this is one of two conditions in order to an alternate series converges, the two conditions are given by the following theorem:

<em>Theorem (Alternating series test)</em>

If a sequence of positive terms {bn} is monotonically decreasing and

<em>\lim_{n \to \infty} b_n = 0<em>, then the alternating series \sum (-1)^{n-1} b_n converges if:</em></em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

then <em>\sum_{n=1}^{\infty}(-1)^{n-1} b_n  converges</em>

<em>Proof</em>

For this proof we just need to consider the sum for a subsequence of even partial sums. We will see that the subsequence is monotonically increasing. And by the monotonic sequence theorem the limit for this subsquence when we approach to infinity is a defined term, let's say, s. So then the we have a bound and then

|s_n -s| < \epsilon for all n, and that implies that the series converges to a value, s.

And this complete the proof.

<em>Part c</em>

An important term is the partial sum of a series and that is defined as the sum of the first n terms in the series

By definition the Remainder of a Series is The difference between the nth partial sum and the sum of a series, on this form:

Rn = s - sn

Where s_n represent the partial sum for the series and s the total for the sum.

Is important to notice that the size of the error is at most b_{n+1} by the following theorem:

<em>Theorem (Alternating series sum estimation)</em>

<em>If  \sum (-1)^{n-1} b_n  is the sum of an alternating series that satisfies</em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

Then then \mid s - s_n \mid \leq b_{n+1}

<em>Proof</em>

In the proof of the alternating series test, and we analyze the subsequence, s we will notice that are monotonically decreasing. So then based on this the sequence of partial sums sn oscillates around s so that the sum s always lies between any  two consecutive partial sums sn and sn+1.

\mid{s -s_n} \mid \leq \mid{s_{n+1} -s_n}\mid = b_{n+1}

And this complete the proof.

5 0
4 years ago
Help please I need this
saw5 [17]

Answer:

12

13

89

Step-by-step explanation:

ez pz

5 0
3 years ago
ASAP i need this TODAY PLEASE)For a survey, students in a class answered these questions: Do you play a sport? Do you play a mus
kondaur [170]

To the nearest percentage point, what percentage of students who play a sport don’t play a musical instrument?

First, using the information given, fill out the chart with the rest of the data (in the image attached)

Then find the number of students who play a sport and don’t play a musical instrument, which in the chart is 11

Place 11 over the total: \frac{11}{25} and convert to a percentage:

44%

5 0
3 years ago
Find the missing measure
uranmaximum [27]

Answer:

x=79*

Step-by-step explanation:

136+60+85+x=360

281+x=360

x=360-281

x=79

8 0
3 years ago
Read 2 more answers
Suppose a teacher finds that the
horsena [70]

Answer:

Scores = 8

Step-by-step explanation:

To solve variation problems, you make mild assumptions and analogies

Let's score be represented with S

Let's Absences be represented with A.

Therefore

S varies inversely as A

S ~ 1/A

S = K/A

The K represents a contant notation so that we can easily figure the variation problem.

When Absences were 2

Scores were 12

S = K/A

12 = K / 2

Cross Multiply.

K = 24.

It means that, S = 24 / A.

For a student with 3 absences, the score would be:

S = 24 / A

S = 24 / 3

S = 8

Math is fun!

5 0
4 years ago
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