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Contact [7]
3 years ago
15

How to round 0.195121951 to the nearest hundredth of a percent

Mathematics
2 answers:
tigry1 [53]3 years ago
5 0

Answer:

You have to look at the second number in the decimal place and round the number to the right of it. 0.20

WINSTONCH [101]3 years ago
5 0

The answer will be 0.190000000

Because you will have to go to the nine.

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Factor the following, I will give 5 stars and thanks.
tigry1 [53]

Answer:

13) n=-3,-7

14) b=-4,-8

15) m=-7

16) a=-5,-7

Step-by-step explanation:

5 0
3 years ago
f f (x) = StartFraction x minus 3 Over x EndFraction and g(x) = 5x – 4, what is the domain of (f circle g) (x)?
Rudik [331]

Answer:

f(g(x))=5-(7/x)

Step-by-step explanation:

f(x)=(x-3)/x

g(x)=5x-4

f(g(x))=((5x-4)-3)/x

f(g(x))=(5x-7)/x

f(g(x))=(5x/x)-7/x

f(g(x))=5-(7/x)

6 0
3 years ago
Help please!!!! if <1 <3 which conclusion can be made?
netineya [11]

Answer:

B. c // d

Step-by-step explanation:

When ∠1 = ∠3, it means that they are corresponding angles and for that to be true, there must be a pair of parallel lines and one line to cut across both of the lines. Thus, we can conclude that c and d are the parallel lines and a is the line that cut across both of them, creating the corresponding angles.

8 0
3 years ago
5. Simpliify.<br> 5.3(-a-2.4b) - 0.4(2a - 0.5b)
Shalnov [3]

Answer:

-5.3a - 12.72b - 8a² + 2ab

6 0
3 years ago
Find the dimensions of a cylinder of volume 17 m3 of minimal cost if the top and bottom are made of material that costs twice as
Viefleur [7K]

Answer:

The answer is below

Step-by-step explanation:

The volume of the cylinder with radius (r) and height (h) is given as:

Volume = πr²h

17 = πr²h

h = 17 / πr²

Let k represent the cost of the side and 2k the cost of the bottom.

The area of the side = 2πrh, hence the cost of the side = k(2πrh)

The area of the top and bottom = 2πr², hence the cost of the top and bottom = 2k(2πr²)

The total cost (T) = cost of side + cost of the top and bottom

T = k(2πrh) + 2k(2πr²)

T = 2kπ(rh + 2r²)

Put h = 17/πr²

T = 2kπ (r×17/πr² + 2r²)

T = 2kπ(17/πr + 2r²)

The minimal cost is at dT/dr = 0

\frac{dT}{dr} =0=\frac{d}{dr} [2k\pi(\frac{17}{\pi r} +2r^2)]\\\\4r-\frac{17}{\pi r^2} =0\\\\4r=\frac{17}{\pi r^2}\\\\r^3=\frac{17}{4\pi }=1.35\\\\r=\sqrt[3]{1.35}\\\\r=1.1\ m\\\\h=\frac{17}{\pi r^2}  =\frac{17}{\pi (1.1)^2} \\\\h=4.42\ m

5 0
3 years ago
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