Answer:
so the answer will be 1
Step-by-step explanation:
An oil tanker can be emptied by the main pump in 5 hours.
An auxilary pump can empty the tanker in 14 hours.
If the main pump is started at 7pm, when should the auxilary pump be started
so that the tanker is emptied by 11pm?
:
Let t = no. of hrs to run the Aux pump
:
The main pump will run 4 hr (7 - 11 pm)
:
Let the completed job = 1; (an empty Tanker)
:
The shared work equation
4%2F5 + t%2F14 = 1
Multiply equation by 70 to get rid of the equation, results:
14(4) + 5t = 70
56 + 5t = 70
5t = 70 - 56
5t = 14
t = 14%2F5
t = 2.8 hrs to run the aux pump
:
2.8 hr = 2 + .8(60) = 2 hrs 48 min
:
Subtract 2:48 from 11:00 = 8:12 PM start the aux pump
;
;
Check solution
4/5 + 2.8/14 =
.8 + .2 = 1
Answer:
For the second image the answer is 1.2
Step-by-step explanation:
The others won’t load in ;-;
SOLUTION:
Let's establish the formula for a cylinder as displayed below:
Let volume of cylinder = V
V = ( Pi )r^2h
Now let's substitute the values from the problem into the formula to find the volume.
V = ?
r = 8
h = 4
V = ( Pi )( 8 )^2( 4 )
V = ( Pi )( 64 )( 4 )
V = ( Pi )( 256 )
V = 256( Pi )
FINAL ANSWER:
Therefore, the answer is:
C. 256( Pi ) units^3
Hope this helps! :)
Have a lovely day! <3
A = wl
Simply divide both sides by w. This is done to isolate the variable we are solving for.
A/w = (wl)/w
A/w = l
Answer: Choice C
