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2 years ago

Which is one purpose of cell division?

Mathematics

1 answer:

Lady_Fox [76]2 years ago

7 0

B, because when the organism divides the cells become specialized and continue to divide.

You might be interested in

What is the slope of the line represented by the equation y= 4/5x - 3

Ivanshal [37]

Answer:

slope is 4/5x

Step-by-step explanation:

its beside the x

8 0

3 years ago

Find the next three terms in the sequence. 4, 7, 11, 15, a.) 3, 6, 9, 12 b.) 18, 21, 24, 27 c.)19, 22, 25, 28

cricket20 [7]

Answer:

C because your adding 4 to it I guess

3 0

3 years ago

Could I get some help? Its simplifying square roots of negative numbers.

Ainat [17]

Answer:

The square root of -100 is 10i.

Step-by-step explanation:

8 0

2 years ago

Last month, customers at a gift shop bought 40 birthday cards,

Iteru [2.4K]

Answer:

32 People

Step-by-step explanation:

I put 40 (Number of birthday cards bought previously) over 125 (Number of expected costumers) and multiplied it by 100 (Total number of card bought previously) to get my answer. Hopefully that helps :)

7 0

2 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t

damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that $\mu = 3$

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472$

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0

2 years ago