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ra1l [238]
3 years ago
14

If the sum of three consecutive odd integers is at most 216, what is the largest possible value of one of those integers?

Mathematics
1 answer:
galben [10]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

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Find the circumference of a circle whose area is equal to 64π^2​
PilotLPTM [1.2K]

Answer:

14 6/7 is the circumference

Step-by-step explanation:

you first of all look for the radius using the formulae multiply both sides by the reciprocal of 22/7

7/22 ×22/7r=64×7/22=224/11{2 4/11)

2 4/11 is the radius

cir =2×22/7×2 4/11

2×22/7× 26/11=104/7

==== =14 6/7

all i can do but am not sure sorry

7 0
2 years ago
Simply your expression<br> 4[(12-2) ²÷4]
lina2011 [118]

Answer:

100

Step-by-step explanation:

Simplify the following:

4 (12 - 2)^2/4

Hint: | Express 4 (12 - 2)^2/4 as a single fraction.

4 (12 - 2)^2/4 = (4 (12 - 2)^2)/4:

(4 (12 - 2)^2)/4

Hint: | Cancel common terms in the numerator and denominator of (4 (12 - 2)^2)/4.

(4 (12 - 2)^2)/4 = 4/4×(12 - 2)^2 = (12 - 2)^2:

(12 - 2)^2

Hint: | Subtract 2 from 12.

| 1 | 2

- | | 2

| 1 | 0:

10^2

Hint: | Evaluate 10^2.

| 1 | 0

× | 1 | 0

| 0 | 0

1 | 0 | 0

1 | 0 | 0:

Answer: 100

8 0
3 years ago
first person who answer correctly gets a brainllest The perimeter of a rectangle is 64 feet. The length of the rectangle is 3 ti
anastassius [24]

Answer:

2(3(8))+2(8)=64

Step-by-step explanation:

Here, w represents the width of the rectangle,

∵ length of the rectangle is 3 times the width of the rectangle,

So, length = 3w,

Since, the perimeter of a rectangle, P = 2(length + width)

= 2(w + 3w)

= 2w + 2(3w)

If P = 64 feet,

⇒ 2w +2(3w) = 64

⇒ 2w + 6w = 64

⇒ 8w = 64

⇒ w = 8

Verification :

P = 2(8) + 2((3(8)) = 16 + 48 = 64 feet

Hence, the first step that should be taken to verify that the width of the rectangle is 8 is 2(3(8))+2(8)=64

Note : a solution obtain from an equation is verified by substituting the value in the equation.

6 0
3 years ago
Slope and your-intercept of y+2x=4
Kruka [31]
Y+2x=4 To get the answer subtract the 2x from both sides making it y = -2x+4 the slope is -2 and the y-intercept is 4
5 0
3 years ago
A kite is being flown at a 45 angle. The string of the kite is 120 feet long. How high is the kite above the point at which the
MrRissso [65]

Answer: The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

Step-by-step explanation:

Given : A kite is being flown at 45^{\circ} . The string of the kite is 120 feet long.  

Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.

Now, in right Δ ABC

\sin45^{\circ}=\frac{AC}{AB}\\\Rightarrow\ \frac{1}{\sqrt{2}}=\frac{AC}{120}\\\Rightarrow\ AC=120\sqrt{2}

hence, The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

5 0
3 years ago
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