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Sindrei [870]
3 years ago
15

Can you help me plz

Mathematics
1 answer:
lesya [120]3 years ago
3 0

Answer:

The answer has to 4 because 0+4=4

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The terminal side of an angle, Theta, whose sine value is One-half
Kazeer [188]

Theta has a reference angle of 30° and is in Quadrant I or II.

Sin(theta) = ½

Basic angle: 30

<h3>What is the reference angle?</h3>

The acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle sandwiched between the terminal side and the x-axis.

Angles: 30,

180-30 = 150

Because sin is positive in quadrants 1 and 2.

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2 years ago
Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that
damaskus [11]

Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

For triangle ABC, we have:

AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4

BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5

CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2

For triangle DEF, we have:

DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2

EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5

FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1

Divide corresponding sides of the triangles to calculate the scale factor k

k = \frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}

This gives

k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}

Evaluate the quotients

k = 2 = 2 = 2

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

Read more about similar triangles at:

brainly.com/question/14285697

3 0
2 years ago
The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.
motikmotik

Answer:

\text{The width of rectangle}=9x\text{ meters}

Step-by-step explanation:

We have been given that the rectangle has an area of 18x^3 square meters and a length of 2x^{2}. We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}

\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}

\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}

Upon substituting our given values in above formula we will get,

\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}

\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}

Using exponent rule for quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\text{The width of rectangle}=9x^{3-2}\text{ meters}

\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}

Therefore, width of our given rectangle will be 9x meters.

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3 years ago
How many moles of water are produced when 3.0 moles of hydrogen gas reacts with
Ronch [10]

Answer: 3.0 moles of water.

3 0
2 years ago
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Yes. since half of 50 is 25 it is correct to say that 18 is less than half
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