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belka [17]
3 years ago
5

A cat with a mass of 4.50 kilograms sits on a ledge 0.800 meters above the ground. What is the potential energy of the cat? 346

J 35.3 J 3.60 J 0.350 J
Physics
2 answers:
Gennadij [26K]3 years ago
6 0
This is a question about converting energy from one form to another. 

<span>While it is sitting on the ledge, it isn't moving, so at that point it doesn't have any kinetic energy. What it has is gravitational potential energy due to its height above the ground. </span>

<span>Just as it lands, it's at ground level, so it doesn't have any gravitational potential energy anymore. </span>

<span>The reason is that on the way down, it sped up, so all its original gravitational potential energy was turned into kinetic energy. </span>

<span>So if you can work out how much potential energy it had to start with, you will know that that is how much kinetic energy it ended up with just before it landed. </span>

<span>potential energy = m * g * h </span>
<span>where m is the mass, g is the acceleration due to gravity and h is the height </span>

potential energy = 4.45 * 9.81 * 0.800 = 35.3 J 
Hope that helps. Please give me Brainlyest answer. :]
Schach [20]3 years ago
3 0

The correct answer to the question is 35.3 J.

CALCULATION:

The mass of the car is given as m = 4.50 kg.

The cat is 0.800 m above the ground.

Hence, height of ledge from ground h = 0.800 m.

We are asked to calculate the potential energy of the body.

The potential energy possessed by the cat at a height h is nothing else than gravitational potential energy.

The gravitational potential energy of a body at a height h is calculated as-

                         Potential energy P.E = mgh.

Here, g is the acceleration due to gravity. Its value is 9.8\ m/s^2

Hence, the potential energy of the cat is calculated as -

                                         P.E = mgh

                                                = 4.50\times 9.8\times 0.800\ J.

                                                =  35.28 J

                                                = 35.3 J                         [ANS]

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1.A body of certain mass is kept at a height of 15m from the ground, taking the value of g as 10m/s find out the mass of the bod
ehidna [41]

Answer:

1.#potential energy = PE, m = mass in kg, g = force of gravity, h= vertical height above the ground.  ** means to the power of ie exponent. * means multiply.

PE = mgh

300 = m(10)(15)

m = 300/(10)(15)

m= 2kg

2. KE = 1/2 mv**2

     = 1/2(50)(50)**2

     = 2500 joules

Explanation

Is as in solution

4 0
3 years ago
Two masses of size m and 4m are connected by a massless thread and are strung over a frictionless pulley of radius R and moment-
tekilochka [14]

Answer:

Total kinetic energy of entire system is 3 mgl

Explanation:

Given two masses: m and 4m.

Since the pulley is frictionless and the thread is massless, the energy here is linked to the two masses.

Total kinetic energy of entire system = decrease in gravitational potential energy of the system.

Therefore, we have :

ΔKE = Δp

ΔKE = 4mgl - mgl

= 3 mgl

Total kinetic energy of entire system is 3 mgl

6 0
3 years ago
Convert 15 joule into erg.​
GuDViN [60]

Answer:

<h2><u>Joule</u><u>:</u></h2>

1 Joule of work is said to be done when a force of 1 Newton is applied to move/displace a body by 1 metre.

1 Joule= 1 Newton × 1 metre

1 Newton is the amount of force required to accelerate body of mass 1 kg by 1m/s²

So units of N is kgm/s²

So,

1 Joule

=1kgm/s² × m

=1kgm²/s²

<h2><u>Erg</u><u>:</u></h2>

1 erg is the amount of work done by a force of 1 dyne exerted for a distance of one centimetre.

1 Erg =1 Dyne × 1 cm

1 dyne is the force required to cause a mass of 1 gram to accelerate at a rate of 1cm/s².

1 Erg=1 gmcm/s² × cm

1 Erg=1 gmcm/s² × cm=1gmcm²/s²

this is what you need to convert 1gmcm²/s² to 1kgm²/s²

<h3><u>what you need to know for conversion</u></h3>

[1gm=0.001kg

1cm²

=1cm ×1cm

=0.01 m × 0.01 m

=0.0001m²

second remains constant

]

So,

1gmcm²/s²

=0.001kg×0.0001m²/s²

=0.001kg×0.0001m²/s² =0.0000001kgm²/s²

Hence,

<h3><u>1 Erg</u><u>=</u><u>0.0000001</u><u> </u><u>Joule</u></h3><h3><u>1</u><u> </u><u>Joule</u><u>=</u><u>1</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>Erg</u></h3>

<h2>⇒15 J=15×10000000 Erg</h2><h2> =150000000 Erg</h2><h2> =1.5×10⁶ Erg</h2>
3 0
3 years ago
Read 2 more answers
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