Answer:
the answer would be "using more heat" btw
Explanation:
Answer:
The magnitude of the average emf induced in the coil is approximately o.32 V.
Explanation:
As, no. of loops = N = 10
Area = 0.23 m^2
Magnetic field = B = 0.047 T
Δt = 0.34 s
These are the given things now we have to find the EMF. So the formula of emf is:
emf = e = N×ΔФ/Δt
Therefore, ΔФ = B . ΔA = BΔAcos(θ)
Since, flux is maximum so θ = 0 and cos(0) = 1
Then,
ΔФ = BA
e = N×(BΔA)/Δt
e = 10×(0.047×0.23)/0.34
e = 0.317 V.
So, we can write it by rounding off the digit
e ≅ 0.32 V.
Answer:5m/s
Explanation:
Kinetic energy=ke=15kj=15x1000j=15000j
Mass=1200kg
Speed=√(2ke/m)
Speed=√(2x15000/1200)
Speed=√(30000/1200)
Speed=√(25)
Speed=5m/s
Answer
given,
length of the track = 200 m
speed of runner 1 = 6.20 m/s
speed of the runner 2 = 5.5 m/s
distance covered by the fastest runner, d = 6.2 t
distance covered by the slow runner,d = 5.50 t + 200
time taken to overtake for the first time
6.2 t = 5.50 t + 200
0.7 t = 200
t = 285.7 s
distance covered from the starting point
d = 6.2 t
d = 6.2 x 285.7
d = 1771.43 m
for next overtaking time taken will be double
t' = 258.7 x 2 = 571.4 s
distance travel by the runner from the starting point
d' = 6.2 t'
d' = 6.2 x 571.4
d' = 3542.68 m