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Sloan [31]
3 years ago
8

How much would $200 invested at 4% interest compounded continuously be worth after 8 years? round your answer to the nearest cen

t
Mathematics
1 answer:
Arlecino [84]3 years ago
7 0

Answer:

424--------------------------------------------------------

                                                                                 

You might be interested in
The ten's digit of a two digit number is 1 more than 4 times the units' digit. if 63 is subtracted from the number, the order of
ser-zykov [4K]
Let x be the digit in the tens place and y be the digit in the ones place.
so, the digit is xy
<span>
The ten's digit of a two digit number is 1 more than 4 times the units' digit.
</span>x = 4y + 1

<span>63 is subtracted from the number, the order of the digits is reversed
</span>10x + y - 63 = 10y + x
9x - 9y = 63

x = 4y + 1 ------------ (1)
9x - 9y = 63  ---------- (2)

Sub (1) into (2)
9(4y + 1) - 9y = 63
36y + 9 - 9y = 63
27y = 63 - 9
27y = 54
y = 2 ------- sub into (1)

x = 4(2) + 1 = 9

x = 9, y = 2
The number is 92

3 0
3 years ago
Please help dont know how
stiks02 [169]

Answer:

90 and 270 maybe neg 270

Step-by-step explanation:

5 0
2 years ago
Please help me with this question!!
Bess [88]

Answer:

x=16 * cos(46)

Step-by-step explanation:

Well, first let's look at our trig identities. We can set up a cosine function using the given angle:

cos (46^{o} ) = \frac{x}{16} (adjacent/hypotenuse)

Then, multiplying both sides by 16 gives us:

x=16 * cos(46)

Hope this helps!

4 0
3 years ago
Find an equation of a degree 3 polynomial (in factored form) with the given zeros of f(x): − 3 , 4 , − 3 . Assume the leading co
oksano4ka [1.4K]

f(x) = x³ + 2x² - 15x - 36 is the equation of a degree 3 polynomial (in factored form) with the given zeros of f(x) are − 3 , 4 , − 3 assuming that the leading coefficient is 1. This can be obtained by formula of polynomial function.

<h3>Find the required equation:</h3>
  • The zeroes or roots of a polynomial function are x values for which          f(x) = 0
  • If the zeroes or roots are r₁, r₂, r₃,... then possible polynomial function is

⇒ f(x) =  a(x - r₁)(x - r₂)(x - r₃)

where a is the leading coefficient

Here in the question it is given that,

  • Polynomial should be with degree 3
  • zeros of f(x) are − 3 , 4 , − 3

By using the formula of polynomial function we get,

⇒ f(x) =  a(x - r₁)(x - r₂)(x - r₃)

⇒ f(x) = 1(x - (-3))(x - (4))(x - (-3))

⇒ f(x) = 1(x + 3)(x - 4)(x + 3)

⇒ f(x) = (x + 3)(x² - x - 12)

⇒ f(x) = x³ - x² - 12x + 3x² - 3x - 36

⇒ f(x) = x³ + 2x² - 15x - 36

Hence f(x) = x³ + 2x² - 15x - 36 is the equation of a degree 3 polynomial (in factored form) with the given zeros of f(x): − 3 , 4 , − 3 assuming that the leading coefficient is 1.

 

Learn more about polynomial function here:

brainly.com/question/12976257

#SPJ1

4 0
1 year ago
Help! Please answer this! Giving all my points away! NO LINKS! Thank you!
Zanzabum

Answer:

13

Step-by-step explanation:

200-187=13

8 0
3 years ago
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