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ruslelena [56]
3 years ago
7

PLEASEEEEEEE HELP with this question

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

second table

Step-by-step explanation:

Out of the 8 options on the spinner, 2 of them are 0's, 1 of them is a 1, 2 of them are 2's and 3 of them are 3's so the probability of spinning a 0, 1, 2 or 3 is 2/8, 1/8, 2/8 or 3/8 which becomes 0.25, 0.125, 0.25 or 0.375 respectively. Therefore, the answer is the second table.

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yes

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2+2+2=6

3+3=6

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Which of the following would give a measurement of area? Thank you
lina2011 [118]

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B

Step-by-step explanation:

5 0
3 years ago
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Answer:

3x+50=6x-10

Step-by-step explanation:

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3 years ago
This season, the probability that the Yankees will win a game is 0.57 and the probability that the Yankees will score 5 or more
NeTakaya

The probability that the Yankees would score fewer than 5 runs when they lose the game is 0.44.

<h3>What is probability?</h3>

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The probability that the Yankees will win a game P(win) = 0.57

The probability that the Yankees will score 5 or more runs in a game is:

P(s>5) = 0.46

The probability that the Yankees lose and score fewer than 5 runs is:

P(s<5) = 0.33

To find the probability that the Yankees would score fewer than 5 runs when they win the game:

This is the case of probabilities of one event and another event together we will multiply the respective probabilities of the event:

= 0.57 + 0.33 - 0.46

= 0.44

Thus, the probability that the Yankees would score fewer than 5 runs when they lose the game is 0.44.

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

5 0
2 years ago
prove the following identity: sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x please provide a proof in some shape form or fash
wolverine [178]

Answer:

Step-by-step explanation:

Hello,

<u><em>Is this equality true ?</em></u>

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

<u>1. let 's estimate the left part of the equation</u>

sec(x)csc(x)(tan(x) + cot(x)) =\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin(x)}{cos(x)}+\dfrac{cos(x)}{sin(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin^2(x)+cos^2(x)}{sin(x)cos(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{1}{sin(x)cos(x)})\\\\\\=\dfrac{1}{cos^2(x)sin^2(x)}

<u>1. let 's estimate the right part of the equation</u>

<u />2+tan^2(x) + cot^2(x)=2+\dfrac{sin^2(x)}{cos^2(x)}+\dfrac{cos^2(x)}{sin^2(x)}\\\\=\dfrac{2cos^2(x)sin^2(x)+cos^4(x)+sin^4(x)}{cos^2(x)sin^2(x)}\\\\=\dfrac{(cos^2(x)+sin^2(x))^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1}{cos^2(x)sin^2(x)}<u />

This is the same expression

So

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

hope this helps

7 0
3 years ago
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