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ruslelena [56]
3 years ago
7

PLEASEEEEEEE HELP with this question

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

second table

Step-by-step explanation:

Out of the 8 options on the spinner, 2 of them are 0's, 1 of them is a 1, 2 of them are 2's and 3 of them are 3's so the probability of spinning a 0, 1, 2 or 3 is 2/8, 1/8, 2/8 or 3/8 which becomes 0.25, 0.125, 0.25 or 0.375 respectively. Therefore, the answer is the second table.

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Can you help me with this it’s so confusing plz help me with both is this
mars1129 [50]

Answer:

First picture: -4,913

Second picture: 20.25

Step-by-step explanation:

-17^5/-17^2 = -17^3

-17 × -17 × -17 = -4913

4.5^5/4.5^3 = 4.5^2

4.5 × 4.5 = 20.25

Do you see how I had the same whole number on the top and bottom? (17 was on top and 17 was on bottom)

The exponents were those tiny numbers you saw.

Whenever you are dividing by the same whole number (-17/-17), you can subtract exponents.

When you multiply the same whole number, you can add the exponents.

Hope this helps! Best of luck :)

5 0
3 years ago
HELP I NEED TO PASS!!!!!
Brilliant_brown [7]
It’s b and d ? Both of those equations are the same if u haven’t noticed
6 0
3 years ago
Determine whether or not there is a congruence between △abc and △def. if there is such a congruence, then give the reason for it
Andru [333]

There is no congruence between the triangles based on the given information. In general, two sides and an angle not between them are insufficient to specify the triangle completely. In this case, the angles that are congruent are adjacent to non-corresponding sides, so even if SSA correspondence were sufficient to ensure congruence, it would not be sufficient in this case.


The appropriate choice is

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4 0
3 years ago
Factor the polynomial completely x^2-x-20
Strike441 [17]

Answer:

(x − 5) (x + 4)

Step-by-step explanation:

x² − x − 20

Factor using AC method:

1 × -20 = -20

Factors of -20 that add up to -1: -5 and 4

Divide by 1 and reduce: -5/1 and 4/1

(x − 5) (x + 4)

5 0
4 years ago
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Join QuestionCove for this, we have plenty of helpers willing to help!!

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3 years ago
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