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3 years ago

-4x-9y=1 -x+2y=-4 send help thanks

1 answer:

6 0

Hey those are linear functions, gotta find Y or X and draw on two axis X/Y. in first y = 4/9x + 1/9. in second y = X/2 - 2.

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Can someone please help me solve this, thank you so much if u help!

malfutka [58]

Answer:

68°

Step-by-step explanation:

The triangle containing the 79° angle is isosceles. That means the other base angle is also 79°. The central angle is ...

V = 180° -2(79°) = 22°

Angle X is the other acute angle in right triangle VWX, so has measure ...

X = 90° -22° = 68°

_____

<em>Additional comment</em>

A tangent makes a right angle with the radius to the point of tangency. W is the point of tangency, so angle VWX is a right angle.

5 0

2 years ago

Help with this exercise too please.

labwork [276]

Area of the triangle at the top=1/2basexheight
1/2x10x 2= 10
Area of rectangle =length xwidth
9x10=90
Total area =area of triangle +area of rectangle
90+10=100m^2

8 0

3 years ago

Let:T : ℝ3→ℝ3 be the transformation that projects each vector x=(x1,x2,x3)onto the plane

dangina [55]

Answer:

Step-by-step explanation:

A linear transformation must satisfy the following properties.

- T(0) = 0.

- For vector a,b then T(a+b) = T(a) + T(b).

- For a vector a and a scalar r, it must happen that T(ra) = rT(a)

In this case we have that T(a,b,c) = (a,0,c).

Note that T(0) = T(0,0,0) = (0,0,0) = 0. So, the first property holds.

Let $a=(a_1,a_2,a_3), b=(b_1,b_2,b_3)$ . Then

$T(a+b) = T((a_1+b_1,a_2+b_2,a_3+b_3)) = (a_1+b_1,0,a_3+b_3) = (a_1,0,a_3)+(b_1,0,b_3) = T(a) + T(b)$

So the second property holds.

Finally, let r be a scalar and let $a=(a_1,a_2,a_3)$ . Then

$T(ra) = T((ra_1,ra_2,ra_3)) = (ra_1,0,ra_3) = r(a_1,0,a_3)= rT(a)$

So, the three properties hold, and therefore, T is a linear transformation.

5 0

3 years ago

Determine the total number of proper subsets of the set of letters from the English alphabet a,b, c, ...,j. The number of proper

Inga [223]

$\{a,b,c,\ldots,j\}$ has ten elements, so any proper subset has at most nine of these elements.

The number of ways of taking any $0\le n\le 9$ letters from this set is given by the binomial coefficient,

$\dbinom{10}n=\dfrac{10!}{n!(10-n)!}$

and in particular, the total number of ways to picking proper subsets is

$\displaystyle\sum_{n=0}^9\binom{10}n=\dbinom{10}0+\dbinom{10}1+\cdots+\dbinom{10}9$

Without computing each term directly, let's instead use a direct result from the binomial theorem, which says

$\displaystyle\sum_{n=0}^N\binom Nna^nb^{N-n}=(a+b)^N$

If we replace $a=b=1$ , then we're left with

$\displaystyle\sum_{n=0}^N\binom Nn=(1+1)^N=2^N$

We can use this to evaluate our sum directly:

$\displaystyle\sum_{n=0}^9\binom{10}n=\sum_{n=0}^{10}\binom{10}n-\binom{10}{10}=2^{10}-1=1023$

8 0

3 years ago

6[2-(5+4x)]-2x=-20+2(1-13x)

Elanso [62]

Answer:

all numbers are solutions

Step-by-step explanation:

3 0

3 years ago

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