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goblinko [34]
3 years ago
5

Which of the following is carried by the blood and then is eliminated from the body? A. Carbon dioxide B. Ammonia C. Heat D.All

the above
Mathematics
1 answer:
forsale [732]3 years ago
7 0

Answer:

its A i believe so

Step-by-step explanation:

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Find the value of each missing variable. y=
e-lub [12.9K]

Step-by-step explanation:

29x - 3 + 15x + 7 = 180° because these two angles are supplementary

if we add like terms

44x + 4 = 180

44x = 176 divide both sides by 44

x = 4

29x - 3 = 13y - 17 because alternate exterior angles has same measurement

since we found the value of x let's rewrite the equation

4 × 29 - 3 = 13y - 17

113 = 13y - 17

130 = 13y divide both sides by 13

10 = y

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3 years ago
Which expression is undefined?<br> ОА<br> A 0:6<br> B. 6:0<br> C-14:3<br> O 0 14 = (-3)<br> D
avanturin [10]

Answer:

c

Step-by-step explanation:

because it would have many solutions

5 0
2 years ago
Common types of data patterns that can be identified when examining a time series plot include all of the following except _____
topjm [15]

Answer:

Vertical is the answer

6 0
2 years ago
There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit
Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a \frac{3}{11} chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is \frac{8}{11}, and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is\frac{2}{11}, and the probability of picking the second red ball is \frac{1}{10} and the probability of picking the green ball is\frac{1}{9}. We want to multiply thm again, as per the multiplication rule like the last problem.

\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}

5 0
3 years ago
Ben Teal lost his weighted
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15 pounds each and 16 watermelons= 240 pounds. (15x16=240)
7 0
3 years ago
Read 2 more answers
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