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aliina [53]
3 years ago
5

The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster os 0.608 meter lo

ng .the average chuckwalla is 0.395 meter long how many times as long is the gila monster as the chuckwalla. To the nearest hungredth
Mathematics
1 answer:
docker41 [41]3 years ago
5 0
The answer is 1.54 meters
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Please help type the integer that represents the correct answer the absolute value of 7
Nadya [2.5K]
The answer is:  " 7 " .
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3 years ago
I need to know this I don’t understand and it is last one
Len [333]

Answer:

The answer is 4x

Step-by-step explanation:

Hope this helped

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stich3 [128]

Answer:

T = (0, 2b)

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Step-by-step explanation:

4 0
3 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

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b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
4 years ago
Pls help me can't figure it out pls someone help me
rusak2 [61]
Did you ever find the answer?
7 0
3 years ago
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