Somebody? I think you can find someone like that in your school... nice profile picture.
Answer:
We know that a^2+b^2=c^2. The 45° angle lets us know that y=x (45+45+90=180), so the problem is y^2+x^2=4sqrt of 2

So you get y^2+x^2=32, and from there, since we know x and y are equal, you can just divide 32 by 2 then take the square root of that, so the answer should be <em><u>4</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>both</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>y</u></em>
Step-by-step explanation:
let me know if I'm wrong lol
To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations
Answer: Multiplying and Dividing Decimals by Powers of 10
When you divide a decimal by a power of 10, simply move the decimal place to the left as many places as there are 0s in the power of 10.
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :

t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,

The above is a quadratic equation. It can be solved by the formula as follows :

Here, a = -16, b = 32 and c = 128

Neglecting negative value, the projectile will land after 4 seconds.