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2 years ago

13

You and your friend chip in to buy a new gaming computer, which costs $1024. How much do each of you pay for the new gaming comp

uter?

1 answer:

Paul [167]2 years ago

5 0

Answer:

512 dollars

Step-by-step explanation:

If you both are paying equal which means half of the total price, it will be 512 dollars each.

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About two twenty-fifths of the male population in the world cannot distinguish red from green. If there are fourteen boys in the

solniwko [45]

About 175 ninth grade boys. 2/25 is equal to 0.08. if we take the 14 students and divide it by 0.08, we can get the total of 175 ninth grade boys.

6 0

3 years ago

If you were to add 5 to my number and then divide by 4, you would get 7

Norma-Jean [14]

Let's make an equation. T will be the number.
(T+5)/4=7
Let's multiply both sides by 4 to get T by itself.
T+5=28
Subtract 5 from both sides.
T=23
Your number is 23.

3 0

3 years ago

Read 2 more answers

How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$

5 0

3 years ago

Dana wants to make cookies. The recipe calls for 2/3 cups of flour for two dozen. She only wants to make one dozen,so how much f

Veseljchak [2.6K]

Answer:

1/3 c flour

Step-by-step explanation:

divide 2/3 in half because you're going from 2 dozen to 1 dozen

2/3 ÷ 2 equals 2/3 x 1/2 which equals 1/3

3 0

3 years ago

Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0

3 years ago